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If y > 2 and \(\frac{x}{6}\)= y, for which of the following expressions can a single numerical value be determined?
I.\(\frac{x-2}{y-2}\)
II.\(\frac{x^2}{y}\)
III.\(\frac{91x}{y}\)
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III
I.\(\frac{x-2}{y-2}\)
II.\(\frac{x^2}{y}\)
III.\(\frac{91x}{y}\)
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III
cathygeorge123
Joined: 28 May 2014
Last visit: 14 Apr 2022
Posts: 64
Given Kudos: 164
Location: Singapore
Concentration: Strategy
Schools: INSEAD Jan'21 Intake
GMAT 1: 590 Q44 V27
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14 Feb 2020, 08:39
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Bunuel
If y > 2 and \(\frac{x}{6}\)= y, for which of the following expressions can a single numerical value be determined?
I.\(\frac{x-2}{y-2}\)
II.\(\frac{x^2}{y}\)
III.\(\frac{91x}{y}\)
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III
I.\(\frac{x-2}{y-2}\)
II.\(\frac{x^2}{y}\)
III.\(\frac{91x}{y}\)
(A) I only
(B) II only
(C) III only
(D) I and III only
(E) I, II, and III
I. (x-2)/(y-2)= (x-2)/[(x/6)-2) ---> the x will not be cancelled out ....(A) is NOK
II. x^2/(y)= 6/x ---> We don't know the value of x .....(B) is NOK
III. 91x/y=91x/(x/6)=546.....(C) is OK
Ans : (C)
General Discussion
17 Sep 2020, 20:29
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Plug in X = 6y for each Y Value in the Terms.
Since Y > 2 (there is NO Upper Bound), if the Y term does NOT Cancel in the Expression, then there is more than ONE Unique Value.
I.
6y - 2 / y - 2 = 2 ( y-1) / (y - 2) = MORE than 1 Value possible
II. (6y)^2 / y = 36*y^2 / y = 36 * y ------ since Y > 2, there is MORE than 1 Value Possible
III. 91 * 6y / y = 91 * 6 = 546 = 1 Unique Value
only III works
Since Y > 2 (there is NO Upper Bound), if the Y term does NOT Cancel in the Expression, then there is more than ONE Unique Value.
I.
6y - 2 / y - 2 = 2 ( y-1) / (y - 2) = MORE than 1 Value possible
II. (6y)^2 / y = 36*y^2 / y = 36 * y ------ since Y > 2, there is MORE than 1 Value Possible
III. 91 * 6y / y = 91 * 6 = 546 = 1 Unique Value
only III works
