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If y = 3x, and z = 2y, then in terms of x, x + y + z =

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Bunuel
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If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   09 Aug 2017, 04:38
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If y = 3x, and z = 2y, then in terms of x, x + y + z =

(A) 10x
(B) 9x
(C) 8x
(E) 6x
(E) 5x
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A
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   09 Aug 2017, 04:57
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Given data:
y = 3x
z = 2y

Therefore, z can be rewritten as 2(3x) = 6x

Since we need to find the value of the expression in terms of x,

x + y + z = x + 3x + 6x = 10x(Option A)
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   09 Aug 2017, 08:57
Bunuel wrote:
If y = 3x, and z = 2y, then in terms of x, x + y + z =

(A) 10x
(B) 9x
(C) 8x
(E) 6x
(E) 5x


Let x = 1

So, y = 3 & z = 6

Hence, \(x + y + z\) = \(1 + 6 + 3\) = \(10\)

Thus, in terms of x the value of \(x + y + z\) = \(10\)

Hence, answer must be (A) \(10x\)
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   15 Aug 2017, 11:45
z = 2y
y = 3x
so z = 2(3x) = 6x

x + 3x + 6x = 10x
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   15 Aug 2017, 14:06
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Bunuel wrote:
If y = 3x, and z = 2y, then in terms of x, x + y + z =

(A) 10x
(B) 9x
(C) 8x
(E) 6x
(E) 5x


Variables in the answer choices tell you to choose your own values! The phrase 'in terms of' is another clue that this will work.

Let's say x = 1.

Then y = 3 and z = 6.

x + y + z = 1 + 3 + 6 = 10.

Plug x into the answer choices to see which one equals 10. In this case it's A.
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink] New post   22 Aug 2017, 11:21
If y = 3x, and z = 2y, then in terms of x, x + y + z =

(A) 10x
(B) 9x
(C) 8x
(E) 6x
(E) 5x

Just substitute the values into the last equation

x+3x+6x=10x,option A
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Re: If y = 3x, and z = 2y, then in terms of x, x + y + z = [#permalink]
22 Aug 2017, 11:21
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