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If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]

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11 Dec 2012, 03:23

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If \(y = \sqrt{5-x}\) where x and y are positive integers, what is the remainder when x is divided by 5?

(1) x < 5

(2) y > 1

Another question from me. No OA as this is my own question. Please let me know if you dont agree with my answer and if so, the reason.. . Here goes.. Source : Me..

If \(y = \sqrt{5-x}\) where x and y are positive integers, what is the remainder when x is divided by 5?

Since square root from a negative number is undefined and \(y\) is a positive integer, then \(5-x>0\) --> \(x<5\). Since also given that \(x\) is positive, then \(0<x<5\), thus \(x\) could be 1, 2, 3 or 4. Now, \(y\) would be an integer only for \(x=1\) or \(x=4\).

If \(x=1\), then \(y=2\). If \(x=4\), then \(y=1\).

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]

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11 Dec 2012, 09:47

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This post received KUDOS

MacFauz wrote:

If \(y = \sqrt{5-x}\) where x and y are positive integers, what is the remainder when x is divided by 5?

(1) x < 5

(2) y > 1

Another question from me. No OA as this is my own question. Please let me know if you dont agree with my answer and if so, the reason.. . Here goes.. Source : Me..

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]

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10 Aug 2013, 06:56

y^2 = 5 -x

x= 5 - y^2

(1).

x=1,4 since x<5

(2).

y>1

x=1 hence REM=1

Hence (B)
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Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]

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06 Oct 2014, 12:48

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Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]

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24 Oct 2016, 06:55

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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