If y and n are positive integers and 450y = N^3 , which of

Question

If y and n are positive integers and 450y = N^3 , which of the following MUST be an integer:

I. y/(3 * 2^2 * 5)

II y/(3^2 * 2 * 5)

III y/(3 * 2 * 5^2)

quangviet512 · Answer

I found I the only answer
Because 450=5^2*3^2*2
So N must be divisable by 3*5*2 => N^3 divisable by 450*5*3*2^2
=> y divisable by 2^2*3*5

MBAlad · Answer

but they are all contain the common factors of 3*5*2 so why aren't the others valid?

MBAlad · Answer

I think I have it. y and N are both integers

450y = N^3/450

450 = 3^2 * 5^2 * 2

Substituting N^3/450 into each of the possibilities gives:

I N^3/ (3^2 * 5^2 * 2)(3 * 2^2 * 5) or N^3/3^3 * 5^3 * 2^3

This is the only answer choice that you can take the cube root of leaving an integer.

cicerone · Answer

Given 450y= N^3
i.e 2 x3^2 x 5^2 x y is a perfect cube.
This will happen provided the minimum value of y is 2^2 x 3 x 5 i.e 60.
So the general value of Y is 60 x k^3
From the given options for any value of k option 1 is true.
So option 1   must   be true.

Regards,

yezz · Answer

If y and n are positive integers and 450y = N^3 , which of the following MUST be an integer:

I. y/(3 * 2^2 * 5)

II y/(3^2 * 2 * 5)

III y/(3 * 2 * 5^2)

THE PART IN READ MEANS THE LEAST POSSIBLE VALUE OF N^3 IT BECAME A FAMOUS GMAT TRICK THESE DAYS :lol:

)

450 = 5^2*3^2*2

THUS Y MUST BE AT LEAST (5*3*2^2) THUS MY ANSWER IS 1

) 450 = 5^2*3^2*2 THUS Y MUST BE AT LEAST (5*3*2^2) THUS MY ANSWER IS 1

Mikhail Bondarenko · Answer

I agree with I, y must contain 60=2^2*5*3 for 450y to be a cube. the only option that divides 2^2 is I

If y and n are positive integers and 450y = N^3 , which of

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