Bunuel
If y is an integer, is y = 0?
(1) When y is divided by an even integer the result is odd.
(2) y/6 is even.
Target question: Does y = 0? Given: y is an integer Statement 1: When y is divided by an even integer the result is oddIf we divide 0 by a number, the result (quotient) will EITHER be 0 OR not defined.
To be more specific, for all non-zero values of k, 0/k = 0
And, if k equals 0, then 0/k is not defined.
Since neither of these cases yields an odd quotient, statement 1 essentially tells us that
y CANNOT equal 0 In other words, we can be certain that the answer to the target question is
NO, y does not equal 0Since we can answer the
target question with certainty, statement 1 is SUFFICIENT
Statement 2: y/6 is even There are several values of y that satisfy statement 2. Here are two:
Case a: y = 0. Here, y/6 = 0/6 = 0, and 0 is even. In this case,
y EQUALS 0Case b: y = 12. Here, y/6 = 12/6 = 2, and 2 is even. In this case,
y does NOT equal 0Since we cannot answer the
target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
Cheers,
Brent