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11 Mar 2022, 09:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:39) correct
13%
(00:36)
wrong
based on 64
sessions
History
Date
Time
Result
Not Attempted Yet
If y is an odd integer, which of the following must be an even integer?
(A) y + 2
(B) y + 6
(C) 2y − 1
(D) 3y
(E) 3y + 1
(A) y + 2
(B) y + 6
(C) 2y − 1
(D) 3y
(E) 3y + 1
11 Mar 2022, 16:28
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Addition and Multiplication rules: (O= odd ; E = even)
E*E = E
E*O = E
O*O = O
E+E = E
E+O = O
O+O = E
We know y is odd. Which MUST give even.
1 and 2: eliminated as we are adding an even number to an odd, hence the result is odd.
3: E*O - O, will give us an even number - an odd ==> odd
4: O*O ==> eliminated
5: O*O + 1 = O + O ==> even
==> E
E*E = E
E*O = E
O*O = O
E+E = E
E+O = O
O+O = E
We know y is odd. Which MUST give even.
1 and 2: eliminated as we are adding an even number to an odd, hence the result is odd.
3: E*O - O, will give us an even number - an odd ==> odd
4: O*O ==> eliminated
5: O*O + 1 = O + O ==> even
==> E
