GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 16 Oct 2018, 03:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If y is not equal to 0 and y is not equal to 1, which is

Author Message
TAGS:

### Hide Tags

Intern
Joined: 12 May 2012
Posts: 19
Location: United States
Concentration: Technology, Human Resources
If y is not equal to 0 and y is not equal to 1, which is  [#permalink]

### Show Tags

Updated on: 14 Jun 2012, 01:22
00:00

Difficulty:

55% (hard)

Question Stats:

63% (02:05) correct 37% (02:17) wrong based on 204 sessions

### HideShow timer Statistics

If y is not equal to 0 and y is not equal to 1, which is greater, x/y or x/(y+1)

(1) x is not equal to 0
(2) x > y

Originally posted by sarb on 14 Jun 2012, 01:18.
Last edited by Bunuel on 14 Jun 2012, 01:22, edited 1 time in total.
Edited the question.
Math Expert
Joined: 02 Sep 2009
Posts: 49892
Re: If y is not equal to 0 and y is not equal to 1, which is  [#permalink]

### Show Tags

14 Jun 2012, 01:34
1
2
If y is not equal to 0 and y is not equal to 1, which is greater, x/y or x/(y+1)

Is $$\frac{x}{y}>\frac{x}{y+1}$$? --> is $$\frac{x}{y}-\frac{x}{y+1}>0$$? --> is $$\frac{xy+x-xy}{y(y+1)}>0$$? --> is $$\frac{x}{y(y+1)}>0$$?

(1) x is not equal to 0. Not sufficient.
(2) x > y. Not sufficient.

(1)+(2) Still not sufficient, for example: if x>0>(y=-1/2) answer is NO but if x>y>0 answer is YES.

_________________
Manager
Status: Preparing myself to break the sound( 700 )-barrier!
Joined: 15 Feb 2011
Posts: 197
Re: If y is not equal to 0 and y is not equal to 1, which is  [#permalink]

### Show Tags

16 Jun 2012, 15:02
Bunuel, is there any easier method to solve this problem? Maybe, a non-algebraic or lesser-algebraic method? :-/
Senior Manager
Status: 1,750 Q's attempted and counting
Affiliations: University of Florida
Joined: 09 Jul 2013
Posts: 498
Location: United States (FL)
Schools: UFL (A)
GMAT 1: 600 Q45 V29
GMAT 2: 590 Q35 V35
GMAT 3: 570 Q42 V28
GMAT 4: 610 Q44 V30
GPA: 3.45
WE: Accounting (Accounting)
Re: If y is not equal to 0 and y is not equal to 1, which is  [#permalink]

### Show Tags

07 Oct 2013, 22:47
You can plug numbers. Based on the question stem, it seems pretty easy to plug and play with some numbers. $$\frac{x}{y}$$ or $$\frac{x}{(y+1)}$$

(1) x is not equal to 0 ----> I think from a quick glance, this is not sufficient because we don't know any thing about y. But just for kicks work through the process. Pick numbers: y= 2 , x=2

$$\frac{2}{2}=1$$ and $$\frac{2}{2+1}=\frac{2}{3}$$ Therefore, $$\frac{x}{y}$$ 1 > 2/3 $$\frac{x}{(y+1)}$$

but if we pick y= -2 , x=-2 then $$\frac{-2}{-2}$$ = 1 and $$\frac{-2}{-2+1}=\frac{-2}{-1}= 2$$, Therefore, $$\frac{x}{y}$$ $$1 < 2$$ $$\frac{x}{(y+1)}$$

So based on the results, we have two answer, therefore the statement N/S

(2) x > y ----> same thing for this statement. Try using a variation of the same number. Make the both positive and both negative but satisfying the parameters of the statement. Pick numbers: y= 2 , x=4

$$\frac{4}{2}=2$$ and $$\frac{4}{2+1}=\frac{4}{3}$$ $$or 1 \frac{1}{3}$$. Therefore, $$\frac{x}{y}$$ $$2 >$$$$1 \frac{1}{3}$$ $$\frac{x}{(y+1)}$$

but if we pick y= -4 , x=-2 then $$\frac{-2}{-4}$$ =$$\frac{1}{2}$$and $$\frac{-2}{-4+1}=\frac{-2}{-3}= \frac{2}{3}$$, Therefore, $$\frac{x}{y}$$ $$.50 < .666$$ $$\frac{x}{(y+1)}$$

So we get two different results from picking numbers that satisfied the parameters in Stmt 2. So this is N/S. When you put the two statements together its also I/S. From Stmt 1, we don't if x is positive or negative. That will have a bearing on the results of the numbers as noted above.

I know its been awhile since you made this post, but the time it took me rationalize this correct answer helped me understand why i got the question wrong. Hope this explanation helps someone else where an algebra equation is not intuitive.
Intern
Joined: 03 Jan 2017
Posts: 30
Re: If y is not equal to 0 and y is not equal to 1, which is  [#permalink]

### Show Tags

16 Feb 2017, 22:56
Q. Is x/Y >X/(Y+1)

X/Y - X/(Y+1)>0
XY+X-XY>0
So the question is
IS X>O?

statement 1. X≠0
Not sufficient as X>0 or X<0

Statement 2. X>Y
Not sufficient as we do not know the sign of Y and the distance between X and Y.

Combine...not sufficient as can't find the sign of x

Ans E

Sent from my MotoG3 using GMAT Club Forum mobile app
Re: If y is not equal to 0 and y is not equal to 1, which is &nbs [#permalink] 16 Feb 2017, 22:56
Display posts from previous: Sort by