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If you roll one fair six-sided die, what is the probability that the

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If you roll one fair six-sided die, what is the probability that the  [#permalink]

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New post Updated on: 16 Oct 2016, 01:16
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If you roll one fair six-sided die, what is the probability that the number is even or less than 4?

(A) 1/6
(B) 1/3
(C) 2/ 3
(D) 3/4
(E) 5/6

Originally posted by NaeemHasan on 15 Oct 2016, 22:37.
Last edited by Bunuel on 16 Oct 2016, 01:16, edited 1 time in total.
Renamed the question.
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Re: If you roll one fair six-sided die, what is the probability that the  [#permalink]

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New post 15 Oct 2016, 22:46
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Total favourable outcomes: 1,2,3 (less than 4), 4,6(even) = 5
Total possible outcome= 6
Probability=5/6.

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Re: If you roll one fair six-sided die, what is the probability that the  [#permalink]

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New post 16 Oct 2016, 03:02
NaeemHasan wrote:
If you roll one fair six-sided die, what is the probability that the number is even or less than 4?

(A) 1/6
(B) 1/3
(C) 2/ 3
(D) 3/4
(E) 5/6


With mithuncherayil

You can take it this way as well -

Possibility that the number is neither even nor less than 4 = 5
Total possible outcome= 6

So, Possibility of outcome 5 is \(\frac{1}{6}\)

Hence , the probability that the number is even or less than 4 is \(1 - \frac{1}{6} = \frac{5}{6}\)

So, Answer will be (E) 5/6

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Re: If you roll one fair six-sided die, what is the probability that the  [#permalink]

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New post 19 Jan 2018, 14:08
Abhishek009 wrote:
NaeemHasan wrote:
If you roll one fair six-sided die, what is the probability that the number is even or less than 4?

(A) 1/6
(B) 1/3
(C) 2/ 3
(D) 3/4
(E) 5/6


With mithuncherayil

You can take it this way as well -

Possibility that the number is neither even nor less than 4 = 5
Total possible outcome= 6

So, Possibility of outcome 5 is \(\frac{1}{6}\)

Hence , the probability that the number is even or less than 4 is \(1 - \frac{1}{6} = \frac{5}{6}\)

So, Answer will be (E) 5/6


how do you put this into the P(A or B) formula? = P(A) + P(B) - P(A&B)??
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Re: If you roll one fair six-sided die, what is the probability that the &nbs [#permalink] 19 Jan 2018, 14:08
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