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If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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06 Nov 2014, 08:58
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Tough and Tricky questions: Algebra. If z is not equal to zero, and \(z = \sqrt{6zs  9s^2}\), then z equals: A. s B. 3s C. 4s D. 3s E. 4s Kudos for a correct solution.
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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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10 Nov 2014, 00:21
\(z = \sqrt{6zs  9s^2}\) Squaring both sides \(z^2 = 6zs  9s^2\) \(z^2  6zs + 9s^2 = 0\) The LHS is a perfect square of (z  3s) \((z  3s)^2 = 0\) z = 3s Answer = B
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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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Updated on: 06 Nov 2014, 14:52
This is how i got the answer. squaring on both the sides gives Z^2 = 6ZS 9S^2 = Z^26ZS+9S^2 = Z(Z3S) 3S(Z3S) = (Z3S) (Z3S) = Z = 3S i will go with B
Originally posted by adymehta29 on 06 Nov 2014, 10:59.
Last edited by adymehta29 on 06 Nov 2014, 14:52, edited 1 time in total.



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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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06 Nov 2014, 11:23
Bunuel wrote: Tough and Tricky questions: Algebra. If z is not equal to zero, and \(z = \sqrt{6zs  9s^2}\), then z equals: A. s B. 3s C. 4s D. 3s E. 4s Kudos for a correct solution.One can easily eliminate A,D and E, as because for any of the values of z for these options, the expression under the root would equal a negative integer. Thus, we are left with only B or C. Easily start with any one, plugin the value of z(say z=4s), this gives the expression under the root as \(5s^2\), which is obviously not correct. B.
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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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06 Nov 2014, 12:09
adymehta29 wrote: This is how i got the answer. squaring on both the sides gives Z^2 = 6ZS 9Z^2 = Z^26ZS+9Z^2 = Z(Z3S) 3S(Z3S) = (Z3S) (Z3S) = Z = 3S i will go with B Agree with your answer. I just think you had some typo (Z mixed with S) in there that might confuse people.



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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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08 Mar 2016, 08:12
Bunuel wrote: Tough and Tricky questions: Algebra. If z is not equal to zero, and \(z = \sqrt{6zs  9s^2}\), then z equals: A. s B. 3s C. 4s D. 3s E. 4s Kudos for a correct solution.Here z^2 = 6zs 9s^2 now using the quadratic formula => z = 6s /2 = 3s hence B
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Re: If z is not equal to zero, and z = 6zs  9s^2, then z equals:
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21 Jul 2016, 09:23
One can easily eliminate D and E as value of z can not be negative because of Square root. By plugging, z = 3s, 3s = \sqrt{6*3s*s  9s^2} then, squaring on both side: 9s^2 = 18s^2  9s^2, we get both sides equal.



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Re: If z in not equal to zero, and z=sqrt(6zs9s^2) , then z
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30 Aug 2019, 02:41
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Re: If z in not equal to zero, and z=sqrt(6zs9s^2) , then z
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