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24 Feb 2026, 00:45
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
48% (03:00) correct
52%
(03:12)
wrong
based on 44
sessions
History
Date
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Not Attempted Yet
Ifrina Ltd.’s revenue in the first and third quarters was 2.00 million and 1.82 million dollars, respectively. Second-quarter revenue was p percent lower than first-quarter revenue, and third-quarter revenue was p percent higher than second-quarter revenue. If fourth-quarter revenue was 2p percent higher than third-quarter revenue, which of the following is closest to the fourth-quarter revenue (in millions of dollars) ?
A. 2.15
B. 2.37
C. 2.42
D. 2.91
E. 3.16
A. 2.15
B. 2.37
C. 2.42
D. 2.91
E. 3.16
24 Feb 2026, 01:24
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kevincan
First quarter = 2 million
Second quarter = a
Third quarter = 1.82 million
Fourth quarter = b
First quarter to second quarter we have a p% decrease.
From, second quarter to third we have a p% increase.
So, 2(1+p/100) ( 1-p/100) = 1.82
1 - p^2 / (100)^2 = (1.82/2)
1 - 0.91 = p^2 / (100^2)
P^2 = 900
p = 30 %
From third to fourth is 2p % increase = 60% increase.
1.82 * (8/5) = 2.91
option D
24 Feb 2026, 03:49
Kudos
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kevincan
When there is an increase and decrease of p% successively, the overall impact is a decrease of p^2/100%.
So third quarter is p^2/100% less than first quarter.
\(\frac{0.18}{2} * 100 = \frac{p^2}{100}\)
\(p=30\)
Fourth quarter revenue is 2p i.e. 60% more than 1.82 mil.
50% more will be 1.82 + .9 =2.72 mil. Another 10% means another .18 mil which means about 2.9 mil.
Answer (D)
Here are a couple of blog posts on it:
https://anaprep.com/arithmetic-profit-o ... e-formula/
https://anaprep.com/arithmetic-successi ... e-changes/
