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AkamaiBrah
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kpadma
Is it 999C4 * (1/2)^4 ?


Kpadma, your answer equals way over 1, with 1 being a certain probability. I don't think that passes a sanity check.
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AB,

Here I come charging again.

P = (997)^2 / (8 * 999 * 998 ) = (approx) 1/8

I think I may be close to the answer, but not sure it the correct answer.
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kpadma
I think I may be close to the answer, but not sure it the correct answer.



sounds like yogi berra.
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kpadma
I think I may be close to the answer, but not sure it the correct answer.


sounds like yogi berra.


Any four cars have an equal chance of leaving the lot first, so we can concentrate on just one specific bunch of four cars. (Whether there are 999 or just 4 cars in the lot is irrelevant). For a given set of four cars, they can leave the lot in 4! or 24 ways, only one of which the license plate numbers will be in increasing order. Hence, the answer is 1/24.
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A nice trick! Remember a question with six letters to be distributed among six envelopes? What is the probability of having them all distributed correctly? 1/6! Again, there is the only right case.



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