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27 Oct 2017, 00:14
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In 1972, what percent (to the nearest percent) of persons of voting age were female?
(A) 52
(B) 53
(C) 62
(D) 64
(E) 72
27 Oct 2017, 04:47
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72/136=9/17, multiply by 6 to make it closer to 100, it would be 54/102,
Taking into account that 54/102 is just a bit lower that 54/100, then requested value should be closer to 53.
Answer B.
Taking into account that 54/102 is just a bit lower that 54/100, then requested value should be closer to 53.
Answer B.
27 Oct 2017, 08:45
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Percent of persons of voting age who were female=\(\frac{72}{136}\)*100
= \(\frac{9}{17}\)*100=\(\frac{900}{17}\) ~53%
Answer B.
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= \(\frac{9}{17}\)*100=\(\frac{900}{17}\) ~53%
Answer B.
Please give kudos, if u liked my post!
