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# In 1972, what percent (to the nearest percent) of persons of voting ag

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Math Expert
Joined: 02 Sep 2009
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In 1972, what percent (to the nearest percent) of persons of voting ag  [#permalink]

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27 Oct 2017, 00:14
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Difficulty:

45% (medium)

Question Stats:

59% (01:33) correct 41% (01:16) wrong based on 71 sessions

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In 1972, what percent (to the nearest percent) of persons of voting age were female?

(A) 52
(B) 53
(C) 62
(D) 64
(E) 72

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Re: In 1972, what percent (to the nearest percent) of persons of voting ag  [#permalink]

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27 Oct 2017, 04:47
72/136=9/17, multiply by 6 to make it closer to 100, it would be 54/102,
Taking into account that 54/102 is just a bit lower that 54/100, then requested value should be closer to 53.
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Re: In 1972, what percent (to the nearest percent) of persons of voting ag  [#permalink]

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27 Oct 2017, 08:45
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Percent of persons of voting age who were female=$$\frac{72}{136}$$*100
= $$\frac{9}{17}$$*100=$$\frac{900}{17}$$ ~53%

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Re: In 1972, what percent (to the nearest percent) of persons of voting ag  [#permalink]

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30 Oct 2017, 14:02
Bunuel wrote:

In 1972, what percent (to the nearest percent) of persons of voting age were female?

(A) 52
(B) 53
(C) 62
(D) 64
(E) 72

The percentage of all voters who were female in 1972 was 72/136, which is 52.9 or roughly 53 percent.

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Re: In 1972, what percent (to the nearest percent) of persons of voting ag &nbs [#permalink] 30 Oct 2017, 14:02
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