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19 Jan 2007, 12:51
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In 1980, the output was 0.8 million. In each of the following year, the output increased a fixed amount. If the total output from 1980 to 1990 is 14.3, what of the range of output per year?
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19 Jan 2007, 12:57
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Let the output increase each year be x. According to the question, x is fixed for each year.
In 1980, output is 0.8 million
In 1981, output would be (0.8 + x) million
In 1982, output would be (0.8 + 2x) million
.
.
.
In 1990, output will be (0.8 + 10x) million
Given total output from 1980 to 1990 to be 14.3 million
i.e., 0.8 + (0.8+x) + (0.8+2x)….+ (0.8+10x) = 14.3 million
8.8 + 55x = 14.3
x = 5.5/55 = 0.1
Range of output for each year = Difference between outputs
Between 1981 and 1980 = x =0.1 million
Between 1990 and 1989 = (0.8+10x) – (0.8+9x) = x = 0.1million
Range = 0.1million
In 1980, output is 0.8 million
In 1981, output would be (0.8 + x) million
In 1982, output would be (0.8 + 2x) million
.
.
.
In 1990, output will be (0.8 + 10x) million
Given total output from 1980 to 1990 to be 14.3 million
i.e., 0.8 + (0.8+x) + (0.8+2x)….+ (0.8+10x) = 14.3 million
8.8 + 55x = 14.3
x = 5.5/55 = 0.1
Range of output for each year = Difference between outputs
Between 1981 and 1980 = x =0.1 million
Between 1990 and 1989 = (0.8+10x) – (0.8+9x) = x = 0.1million
Range = 0.1million
22 Jan 2007, 21:35
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withme
Good one
:-D
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
