It is currently 21 Mar 2018, 19:06

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In 1995 Division A of Company X had 4850 customers. If there

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Intern
Joined: 12 Feb 2009
Posts: 24
In 1995 Division A of Company X had 4850 customers. If there [#permalink]

### Show Tags

08 May 2009, 08:22
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

In 1995 Division A of Company X had 4850 customers. If there were 86 service errors in Division A that year, what was the service error rate in number of service errors per 100 customers for Division B of Company X?

(1) In 1995 the overall service error rate for Divisions A and B combined was 1.5 service errors per 100 customers

(2) In 1995 Division B had 9350 customers, none of whom are customers of A.

Why isn't (1) alone sufficient?

((86/4850)*100))+(X*100)=1.5

I think i see now. You're taking a weighted avg, so can't solve for X without knowing the weight?

Really is
((86/4850)*100))+(X/Y*100)=1.5

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Senior Manager
Joined: 08 Jan 2009
Posts: 317
Re: Word Translations [#permalink]

### Show Tags

08 May 2009, 18:09
What you did is Total Avg = (Avg) A + (Avg) B .

The above eqn is does not hold good. I took two sets of numbers
A = ( 2,4,7,8) b =( 2,3,6,7,5) where Sum A = 21 and Sum B = 23
21/4 + 23/5 /= 45/8
9.45 /= 5.5

So Total Avg = Sum of terms in A and B / No of terms.

i think both statements would be needed to solve. Correct me if i am wrong.
Re: Word Translations   [#permalink] 08 May 2009, 18:09
Display posts from previous: Sort by

# In 1995 Division A of Company X had 4850 customers. If there

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.