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19 Sep 2019, 04:09
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
93% (01:11) correct
7%
(02:14)
wrong
based on 57
sessions
History
Date
Time
Result
Not Attempted Yet
In 2007, Mike participated in a chess tournament in which he had a 1/4 chance of winning. In 2008, Ben participated in the same tournament and had a 1/3 chance to win. In 2009, Rob participated in that tournament and had a 1/6 chance to win. Assuming that all three events are independent, what's the probability that Mike and Ben won their tournaments but Rob didn't win his?
A. 5/72
B. 5/12
C. 1/2
D. 7/12
E. 67/72
A. 5/72
B. 5/12
C. 1/2
D. 7/12
E. 67/72
19 Sep 2019, 04:16
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Bunuel
Required Probability = Mike wins & Ben wins & Rob doesn’t win
= 1/4*1/3*5/6
= 5/72
IMO Option A
Posted from my mobile device
General Discussion
19 Sep 2019, 08:12
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Bunuel
WIN for
Mike ; 1/4
Ben; 1/3
Rob; 1/6
Loss for
Mike; 3/4
Ben; 2/3
Rob;5/6
probability that Mike and Ben won their tournaments but Rob didn't win his
1/4*1/3*5/6 ; 5/72
IMO A
