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In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass

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In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass [#permalink]

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New post 10 May 2017, 12:17
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E

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83% (01:26) correct 17% (01:29) wrong based on 75 sessions

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In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?

A. 560
B. 654.5
C. 768
D. 864
E. 896

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New post 10 May 2017, 12:22
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E.

6(x)*5= 480

X = 16

Plug in and get 896

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Re: In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass [#permalink]

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New post 10 May 2017, 13:30
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SajjadAhmad wrote:
In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?

A. 560
B. 654.5
C. 768
D. 864
E. 896

I suspect this method may be a slightly unorthodox, but I often set up equations wrong on rate questions, so I drew a table:
Attachment:
CONSUMPTION - RATE - TABLE.jpg
CONSUMPTION - RATE - TABLE.jpg [ 35.95 KiB | Viewed 883 times ]


Because this is a rate question that resembles the "multiple workers" at unknown individual rate (where total work is analogous to total number of gallons consumed, as in pool-draining rate questions), I drew a table.

TOTAL gallons consumed / [total # of cars * total hrs gas is consumed] = RATE of individual car's consumption (see second column)

\(\frac{480}{6*5}\)= \(\frac{480}{30}\) = 16 gallons of gas per hour for INDIVIDUAL car

Now we have individual rate of consumption, such that (# of cars)*(rate of consumption)*(hours spent consuming) = TOTAL gallons consumed (see second row)

7*16*8 = 896
Answer E

I hope this method isn't incorrect. SajjadAhmad ?
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In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass [#permalink]

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New post 10 May 2017, 14:05
SajjadAhmad wrote:
In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?

A. 560
B. 654.5
C. 768
D. 864
E. 896


480/(6*5)=16 gallons per car per hour
16*7*8=896 gallons
E
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Re: In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass [#permalink]

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New post 10 May 2017, 14:12
30(5 cars*6 hours) car hours consumes 480 gallons of fuel.
We need to find how much 56 car hour consume? (7 cars * 8 hours)

30 ---- 480
56 ---- x

Cross multiplying and solving for x,
30x = 480*56
x = 16*56 = 896(Option E)
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Re: In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass [#permalink]

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New post 15 May 2017, 17:32
1
SajjadAhmad wrote:
In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?

A. 560
B. 654.5
C. 768
D. 864
E. 896


Since 6 cars consume 480 gallons, one car consumes 480/6 = 80 gallons in 5 hours. Thus, the consumption rate for each car is 80/5 = 16 gallons per hour.

Since there are 7 cars, they will consume a total of 16 x 7 = 112 gallons per hour. Since the race takes 8 hours, all 7 cars will consume 112 x 8 = 896 gallons of gas.

Answer: E
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Re: In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Ass   [#permalink] 15 May 2017, 17:32
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