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10 May 2017, 12:17
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In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?
A. 560
B. 654.5
C. 768
D. 864
E. 896
A. 560
B. 654.5
C. 768
D. 864
E. 896
gmathopeful19
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10 May 2017, 12:22
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E.
6(x)*5= 480
X = 16
Plug in and get 896
Posted from my mobile device
6(x)*5= 480
X = 16
Plug in and get 896
Posted from my mobile device
10 May 2017, 13:30
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SajjadAhmad
In a 5-hour race, 6 cars consumed 480 gallons of gas between them. Assuming a constant rate of consumption, how much gas would be consumed by 7 cars in an 8-hour race?
A. 560
B. 654.5
C. 768
D. 864
E. 896
I suspect this method may be a slightly unorthodox, but I often set up equations wrong on rate questions, so I drew a table:A. 560
B. 654.5
C. 768
D. 864
E. 896
Attachment:
CONSUMPTION - RATE - TABLE.jpg [ 35.95 KiB | Viewed 2954 times ]
Because this is a rate question that resembles the "multiple workers" at unknown individual rate (where total work is analogous to total number of gallons consumed, as in pool-draining rate questions), I drew a table.
TOTAL gallons consumed / [total # of cars * total hrs gas is consumed] = RATE of individual car's consumption (see second column)
\(\frac{480}{6*5}\)= \(\frac{480}{30}\) = 16 gallons of gas per hour for INDIVIDUAL car
Now we have individual rate of consumption, such that (# of cars)*(rate of consumption)*(hours spent consuming) = TOTAL gallons consumed (see second row)
7*16*8 = 896
Answer E
I hope this method isn't incorrect. SajjadAhmad ?
