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08 Apr 2015, 05:36
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (01:44) correct
25%
(01:36)
wrong
based on 264
sessions
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In a box containing action figures of the three Fates from Greek mythology, there are three figures of Clotho for every two figures of Atropos, and five figures of Clotho for every four figures of Lachesis. What is the least number of action figures that could be in the box?
A. 10
B. 12
C. 15
D. 27
E. 37
A. 10
B. 12
C. 15
D. 27
E. 37
This is a problem from the Fractions, Decimals & Percents Manhattan guide.
In a box containing action figures of the three Fates from Greek mythology, there are three figures of Clotho for every two figures of Atropos, and five figures of Clotho for every four figures of Lachesis. What is the least number of action figures that could be in the box?
This is how I went about solving the problem.
3C=2A - Equation (1)
5C=4L - Equation (2)
Plugging in values for L,A and C that satisfy both the above equations. Plugging the value of L as 5 I get the value of C as 4 and A as 6 (All three positive integers). L+A+C = 15.
What is wrong in this approach?
he answer to this problem is 37.
In a box containing action figures of the three Fates from Greek mythology, there are three figures of Clotho for every two figures of Atropos, and five figures of Clotho for every four figures of Lachesis. What is the least number of action figures that could be in the box?
This is how I went about solving the problem.
3C=2A - Equation (1)
5C=4L - Equation (2)
Plugging in values for L,A and C that satisfy both the above equations. Plugging the value of L as 5 I get the value of C as 4 and A as 6 (All three positive integers). L+A+C = 15.
What is wrong in this approach?
he answer to this problem is 37.
08 Apr 2015, 23:45
Kudos
Bookmarks
Hi cafecorridor,
In this question, we're given two facts about the ratios of 3 items:
1) There are 3 figures of Clotho for every 2 figures of Atropos
2) There are 5 figures of Clotho for every 4 figures of Lachesis.
We're asked for the LEAST number of action figures that could be in the box?
From the given ratios, we know that:
1) The number of figures of Clotho MUST be a multiple of 3 AND a multiple of 5
2) The number of figures of Atropos MUST be an equivalent multiple of 2
3) The number of figures of Lachesis MUST be an equivalent multiple of 4
To figure out the LEAST number of figures, we need to make the each of these numbers as SMALL as possible.
The smallest possible number of Clotho figures is 15.
IF....
Clotho = 15
Atropos = 10
Lachesis = 12
Total number of figures = 15+10+12 = 37
Since this question requires very little in the way of manipulation, it's not that difficult of a question. You'll likely see at least one ratio-based question that's conceptually similar to this one on Test Day.
GMAT assassins aren't born, they're made,
Rich
In this question, we're given two facts about the ratios of 3 items:
1) There are 3 figures of Clotho for every 2 figures of Atropos
2) There are 5 figures of Clotho for every 4 figures of Lachesis.
We're asked for the LEAST number of action figures that could be in the box?
From the given ratios, we know that:
1) The number of figures of Clotho MUST be a multiple of 3 AND a multiple of 5
2) The number of figures of Atropos MUST be an equivalent multiple of 2
3) The number of figures of Lachesis MUST be an equivalent multiple of 4
To figure out the LEAST number of figures, we need to make the each of these numbers as SMALL as possible.
The smallest possible number of Clotho figures is 15.
IF....
Clotho = 15
Atropos = 10
Lachesis = 12
Total number of figures = 15+10+12 = 37
Since this question requires very little in the way of manipulation, it's not that difficult of a question. You'll likely see at least one ratio-based question that's conceptually similar to this one on Test Day.
GMAT assassins aren't born, they're made,
Rich
General Discussion
08 Apr 2015, 05:47
Kudos
Bookmarks
cafecorridor
Three figures of Clotho for every two figures of Atropos --> C:A = 3:2, so 2C = 3A, not 3C=2A.
Five figures of Clotho for every four figures of Lachesis --> C:L = 5:4, so 4C = 5L, not 5C=4L.
Hope it's clear.
