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23 Apr 2025, 00:30
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D
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In a certain box, the ratio of red marbles to blue marbles is 4 to 5, and the ratio of green to blue marbles is 2 to 3. What is the least number of marbles that could be present in the box?
A) 14
B) 15
C) 32
D) 37
E) 43
A) 14
B) 15
C) 32
D) 37
E) 43
23 Apr 2025, 04:07
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Bunuel
The ratio of red : blue = 4:5
The ratio of blue : green = 3:2
Blue is 5 and 3 in the ratios. LCM is 15.
Then, 3* (4:5) = 12:15 = red: blue.
Multiplying with 5* (3:2) = 15:10 = blue : green
Red: Blue : Green = 12k : 15k : 10k
Total marbles = 12k + 15k +10k = 37k
Least number of marbles is when K = 1 = 37
Option D
23 Apr 2025, 08:37
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In a certain box, the ratio of red marbles to blue marbles is 4 to 5, and the ratio of green to blue marbles is 2 to 3. What is the least number of marbles that could be present in the box?
R:B= 4:5 and G:B=2:3
R:B:G= 12:15:10
Least number of marbles in the box= 12x+15x+10x= 37x =37
(When x is 1, we get least number of marbles in the box)
Answer: D
R:B= 4:5 and G:B=2:3
R:B:G= 12:15:10
Least number of marbles in the box= 12x+15x+10x= 37x =37
(When x is 1, we get least number of marbles in the box)
Answer: D
