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18 Apr 2022, 22:56
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (01:38) correct
30%
(01:45)
wrong
based on 470
sessions
History
Date
Time
Result
Not Attempted Yet
In a certain district, 75% of all voters are conservative, and 60% of conservatives voted for candidate A. If candidate A received 50% of all votes, what percent of non-conservative voters supported candidate A?
(A) 5%
(B) 20%
(C) 25%
(D) 45%
(E) 55%
(A) 5%
(B) 20%
(C) 25%
(D) 45%
(E) 55%
19 Apr 2022, 00:34
Kudos
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If the total number of candidates are 100 then :
75 are conservatives and 25 are Non-Conservatives
Out of 75 people 60% voted for A ==> \(\frac{75*60}{100}\)
Lets assume, out of 25 L% voted for A
so total votes that A received is :
\(\frac{(75*60)}{100 } \) + \(\frac{ (25*L)}{100}\)
we know that total votes that a received is 50% (as we have assumed 100 people voted so he/she simply received 50 votes)
equating these 2 we get the percentage of non-conservatives who voted for A
\(\frac{(75*60)}{100 } \) + \(\frac{ (25*L)}{100}\) = 50
L=20
75 are conservatives and 25 are Non-Conservatives
Out of 75 people 60% voted for A ==> \(\frac{75*60}{100}\)
Lets assume, out of 25 L% voted for A
so total votes that A received is :
\(\frac{(75*60)}{100 } \) + \(\frac{ (25*L)}{100}\)
we know that total votes that a received is 50% (as we have assumed 100 people voted so he/she simply received 50 votes)
equating these 2 we get the percentage of non-conservatives who voted for A
\(\frac{(75*60)}{100 } \) + \(\frac{ (25*L)}{100}\) = 50
L=20
03 Jun 2025, 11:08
Kudos
Bookmarks
| CONS | non CONS | TOT | |
| A | 60% * 75 = 45 | 5 | 50 |
| no A | 50 | ||
| TOT | 75 | 25 | 100 |
| =2 : 25 * 100 =20% |
Assumption: total = 100
