Bunuel wrote:
In a certain factory, 20 employees work in five divisions. No two divisions have the same number of employees. How many employees are there in the division that has the least number of employees?
(1) The median number of workers in the five divisions is 4.
(2) The number of employees in the second-smallest division is 3.
Statement 1:Let us try the case with the least number of employees = 2, then we can confirm we must have 2, 3, and 4 for the three divisions of least employees. The other two divisions must be \(20 - 2 - 3 - 4 = 11\) employees in total, thus 5 and 6 since they must be larger than 4.
We can subtract 1 from the division with the least employees and add it to the division with the most, thus 1, 3, 4, 5, 7 is also a viable arrangement. Then there are two possible values, insufficient.
Statement 2:Use the two cases above. Insufficient.
Combined:Both cases we listed in statement 1 are still viable, insufficient.
Ans: E
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