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# In a certain hardware store, 3 percent of the lawnmowers need new labe

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Math Expert
Joined: 02 Sep 2009
Posts: 58402
In a certain hardware store, 3 percent of the lawnmowers need new labe  [#permalink]

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18 Feb 2019, 01:39
00:00

Difficulty:

25% (medium)

Question Stats:

78% (01:21) correct 22% (01:43) wrong based on 18 sessions

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In a certain hardware store, 3 percent of the lawnmowers need new labels. If the price per label is \$4 and the total cost for new lawnmower labels is \$96, how many lawnmowers are in the hardware store?

A. 1,600
B. 800
C. 240
D. 120
E. 24

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Joined: 31 Oct 2013
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Re: In a certain hardware store, 3 percent of the lawnmowers need new labe  [#permalink]

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18 Feb 2019, 01:42
Bunuel wrote:
In a certain hardware store, 3 percent of the lawnmowers need new labels. If the price per label is \$4 and the total cost for new lawnmower labels is \$96, how many lawnmowers are in the hardware store?

A. 1,600
B. 800
C. 240
D. 120
E. 24

Total cost of lawnmower = 96.

cost per lawnmower = 4

Number of lawnmower = 96 /4 = 24.

(24/3) * 100 = 800.

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Re: In a certain hardware store, 3 percent of the lawnmowers need new labe  [#permalink]

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18 Feb 2019, 01:57
Bunuel wrote:
In a certain hardware store, 3 percent of the lawnmowers need new labels. If the price per label is \$4 and the total cost for new lawnmower labels is \$96, how many lawnmowers are in the hardware store?

A. 1,600
B. 800
C. 240
D. 120
E. 24

upon reviewing given answer options we can say that only a & b are options where we get integer value for 3% of total lawnmowers

so
96\$ is cost of new lawnmomer ; 96/4 = 24
and 800 *.03 = 24
IMO B
Re: In a certain hardware store, 3 percent of the lawnmowers need new labe   [#permalink] 18 Feb 2019, 01:57
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