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Pritishd
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In a certain high school graduating class, 60 percent of the students. 19 Oct 2017, 02:39
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E
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85% (hard)

Question Stats:

52% (02:40) correct 48% (02:49) wrong based on 204 sessions

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In a certain high school graduating class, 60 percent of the students plan to attend college, and 40 percent of the students have grade point averages (GPAs) of 3.0 or above. If 30 percent of the students who plan to attend college have GPAs of 3.5 or above, how many of the students who plan to attend college have GPAs of 3.5 or above?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
(2) 90 of the students in the graduating class have GPAs of 3.5 or above.
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E
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In a certain high school graduating class, 60 percent of the students. 05 Nov 2017, 10:34
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This one is a really tricky question. Took me some time to understand what is asked.
Basically question is giving all the percentages, and asking you to tell the exact number.



This table represents the given data (30% of 60% is 18%)
Question is asking how many students does 18% represent.

1. We are give x+18% is 90.
We can't find how much is 18% from this.
Insufficient

2. Here we are given 18+y% is 90.
We still can't find.
Insufficient.

Both.
Even after using both. We would not be able to find the values of x,y,z.
The statements just help us understand how many students do these percentages represent. Without there values, we can't tell how many is 18%.

E.
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In a certain high school graduating class, 60 percent of the students. 12 Dec 2017, 23:10
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I thought each of them was enuf to solve.
So the total students = a
Information given:
Those who plan to go to college = 0.6a
Those who have GPA 3.0 above = 0.4a -> those who have GPA 3.5 above = 0.6a
30% of 0.6a = 0.18a Those who plan to attend college and have GPA 3.5 above -> 0.6a - 0.18a = 0.42a - Those who plan to attend to college and have GPA 3.0 above
Question: 0.18a = ?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
0.42a = 90
=> We will know the value of a -> 0.18a
=> Suf

(2) 90 of the students in the graduating class have GPAs of 3.5 or above.
0.6a = 90
=> Like (1)
=> Suf

Can anyone please correct me?
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In a certain high school graduating class, 60 percent of the students. 12 Dec 2017, 23:59
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lichting
In a certain high school graduating class, 60 percent of the students plan to attend college, and 40 percent of the students have grade point averages (GPAs) of 3.0 or above. If 30 percent of the students who plan to attend college have GPAs of 3.5 or above, how many of the students who plan to attend college have GPAs of 3.5 or above?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
(2) 90 of the students in the graduating class have GPAs of 3.5 or above.


I thought each of them was enuf to solve.
So the total students = a
Information given:
Those who plan to go to college = 0.6a
Those who have GPA 3.0 above = 0.4a -> those who have GPA 3.5 above = 0.6a
30% of 0.6a = 0.18a Those who plan to attend college and have GPA 3.5 above -> 0.6a - 0.18a = 0.42a - Those who plan to attend to college and have GPA 3.0 above
Question: 0.18a = ?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
0.42a = 90
=> We will know the value of a -> 0.18a
=> Suf

(2) 90 of the students in the graduating class have GPAs of 3.5 or above.
0.6a = 90
=> Like (1)
=> Suf

Can anyone please correct me?
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One mistake you are making is marked in red.

40 percent of the students have grade point averages (GPAs) of 3.0 or ABOVE, so 60 percent of the students have grade point averages (GPAs) of BELOW 3.0.
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In a certain high school graduating class, 60 percent of the students. 13 Dec 2017, 00:27
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E? both looks insufficient..even after combining..tried both percent and set/subset way..some or other data just seems to be missing..correct me if i am wrong..expert advice recommended

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In a certain high school graduating class, 60 percent of the students. 13 Dec 2017, 01:42
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Bunuel
lichting
In a certain high school graduating class, 60 percent of the students plan to attend college, and 40 percent of the students have grade point averages (GPAs) of 3.0 or above. If 30 percent of the students who plan to attend college have GPAs of 3.5 or above, how many of the students who plan to attend college have GPAs of 3.5 or above?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
(2) 90 of the students in the graduating class have GPAs of 3.5 or above.


I thought each of them was enuf to solve.
So the total students = a
Information given:
Those who plan to go to college = 0.6a
Those who have GPA 3.0 above = 0.4a -> those who have GPA 3.5 above = 0.6a
30% of 0.6a = 0.18a Those who plan to attend college and have GPA 3.5 above -> 0.6a - 0.18a = 0.42a - Those who plan to attend to college and have GPA 3.0 above
Question: 0.18a = ?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
0.42a = 90
=> We will know the value of a -> 0.18a
=> Suf

(2) 90 of the students in the graduating class have GPAs of 3.5 or above.
0.6a = 90
=> Like (1)
=> Suf

Can anyone please correct me?

One mistake you are making is marked in red.

40 percent of the students have grade point averages (GPAs) of 3.0 or ABOVE, so 60 percent of the students have grade point averages (GPAs) of BELOW 3.0.
Show more

Thanks Bunuel. so the same mistake with this one as well, right?
30% of 0.6a = 0.18a Those who plan to attend college and have GPA 3.5 above ->0.6a - 0.18a = 0.42a - Those who plan to attend to college and have GPA 3.0 above
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In a certain high school graduating class, 60 percent of the students. 21 Dec 2017, 10:42
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Could anyone please explain why the answer is E?
It will be helpful.
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In a certain high school graduating class, 60 percent of the students. 08 Sep 2019, 14:17
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VeritasKarishma
Can you please explain this question?

Thank you.
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In a certain high school graduating class, 60 percent of the students. 10 Sep 2019, 01:01
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Pritishd
In a certain high school graduating class, 60 percent of the students plan to attend college, and 40 percent of the students have grade point averages (GPAs) of 3.0 or above. If 30 percent of the students who plan to attend college have GPAs of 3.5 or above, how many of the students who plan to attend college have GPAs of 3.5 or above?

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.
(2) 90 of the students in the graduating class have GPAs of 3.5 or above.
Show more

Attachment:
IMG_8077.JPG
IMG_8077.JPG [ 2.28 MiB | Viewed 3920 times ]

This is what the question stem gives us. We need to know the value of the shaded region (the cross hatched region).

(1) 90 of the students who plan to attend college have GPAs of 3.0 or above.

This tells us that the shaded region + dotted region = 90.
How much is the shaded region out of it, we do not know. Not sufficient.

(2) 90 of the students in the graduating class have GPAs of 3.5 or above.

30% of T = 90
T = 300
So Students planning to attend college = 60% of T = 60% of 300 = 180
No of students with GPA > 3.0 = 40% of T = 40% of 300 = 120
Don't know the shaded region. Insufficient.

Using both, this is the info we have:
Attachment:
IMG_1914.JPG
IMG_1914.JPG [ 2.58 MiB | Viewed 3949 times ]

180 + 120 - 90 = 210 (no of students planning to attend college or with GPA > 3.0)
But we still don't know the value of cross hatched area. Let's try to give it 2 different values to see if all works in both cases.

Say the cross hatched area is 80. Then the dotted region is 10.
Say the cross hatched area is 60. Then the dotted region is 30.
Works in both cases. Not sufficient.

Answer (E)
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In a certain high school graduating class, 60 percent of the students. 17 Dec 2023, 11:40
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