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25 Mar 2026, 11:26
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
63% (02:26) correct
37%
(03:41)
wrong
based on 30
sessions
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In a certain marketing course, the final grade is a weighted average of the midterm exam, the final exam, and the group project, with the midterm and project having the same weight. One student received scores of 80 on the midterm, 70 on the final exam, and 90 on the project, and earned a final grade of 73. Carlos received scores of 70 on the midterm, 80 on the final exam, and 70 on the project. What was Carlos’s final grade?
A) 76
B) 76.5
C) 77
D) 77.5
E) 78
A) 76
B) 76.5
C) 77
D) 77.5
E) 78
02 May 2026, 23:07
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Let the weights be as follows:
Midterm exam: w
Final exam: w'
Group project: w
As the final grade is a weighted average of the above three:
(80w + 70w' + 90w)/(2w + w') = 73
170w + 70w' = 146w + 73w'
w' = 8w
Given: Carlos received scores of 70 on the midterm, 80 on the final exam, and 70 on the project. To calculate Carlos' final grade, we would have to compute the weighted average of the midterm, final exam and the project:
(70w + 80w' + 70w)/(2w + w') = (140w + 80w')/(2w + w')
=> (140w + 80(8w))/(2w + 8w)
=> (140w + 640w)/(10w)
=> 78
Hence, the correct answer is Option E - 78.
Hope this helps!
Midterm exam: w
Final exam: w'
Group project: w
As the final grade is a weighted average of the above three:
(80w + 70w' + 90w)/(2w + w') = 73
170w + 70w' = 146w + 73w'
w' = 8w
Given: Carlos received scores of 70 on the midterm, 80 on the final exam, and 70 on the project. To calculate Carlos' final grade, we would have to compute the weighted average of the midterm, final exam and the project:
(70w + 80w' + 70w)/(2w + w') = (140w + 80w')/(2w + w')
=> (140w + 80(8w))/(2w + 8w)
=> (140w + 640w)/(10w)
=> 78
Hence, the correct answer is Option E - 78.
Hope this helps!
