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mikemcgarry
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This is a repeated question... have solved it detailed below

Answer = B = 70

in-a-certain-school-there-are-80-freshmen-100-sophomores-and-220-up-187208.html?fl=similar
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the answer should be B we can solve it by suing matrix method .
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Please see attached file below
Correct answer is (B) 70
Attachments

ABC.png
ABC.png [ 30.38 KiB | Viewed 4095 times ]

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First step is calculating total no. of students which is 400 and then neglecting C for the calculation as it contains only Frshman. Out of A and B we can quickly cal total no. of B which is 0.30 * 400 = 120 and then out of which half is upperman I.e. 60 remaining half is 60 which is divided into 30 and 30

So out of total 100 shopomores 30 are from B so rest are from A i.e. 70

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In a certain school, there are 80 Freshmen, 100 Sophomores, and 220 Upperclassmen, drawn from three cities: A, B, and C. Sixty percent of students are from A, 30% from B, the rest from C, and all these students from C are freshmen. Half the student from B are upperclassman, and the rest are split evenly between the other two grades. How many sophomores are from A?
(A) 60
(B) 70
(C) 80
(D) 90
(E) 100



Solution:

We see that there are a total of 80 + 100 + 220 = 400 students from the three cities. Thus, 400 x 0.6 = 240 students are from A, 400 x 0.3 = 120 from B, and 400 - 240 - 120 = 40 from C. Since half the students from B are upperclassmen, 120/2 = 60 students from B are upperclassmen. Since the rest are split evenly between the other two grades, 30 are freshmen and 30 are sophomores. Since all the students from C are freshmen, we see that no sophomores (and no upperclassmen) are from C. Thus, the remaining 100 - 30 = 70 sophomores must be from A.

Answer: B
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First step is calculating total no. of students which is 400 and then neglecting C for the calculation as it contains only Frshman. Out of A and B we can quickly cal total no. of B which is 0.30 * 400 = 120 and then out of which half is upperman I.e. 60 remaining half is 60 which is divided into 30 and 30

So out of total 100 shopomores 30 are from B so rest are from A i.e. 70

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1. Total Freshmen = 80

2. Total Sophomores = 100

3. Total Upperclassmen = 220

4. Net people = 80+100+220 = 400

5. 60% from A =60100∗400=240=60100∗400=240

6. 30% from B =30100∗400=120=30100∗400=120

7. Remaining from C = 400 - (240+120) = 40

8. All students of C are Freshmen = 40

9. Half the student from B are upperclassman = 120/2 = 60

10. rest are split evenly between the other two grades = 30

11. rest are split evenly between the other two grades = 30

12. How many sophomores are from A = 100 - 30 = 70
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