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05 Oct 2021, 11:42
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We can quickly solve using options
Lower limit has to be less than 0.0001 because we are dividing by 4
So we can reject A(0.0025>0.0001) & B(0.00025>0.0001)
Instead of dividing, I multiplied lower limit of C to avoid error in decimals
0.000025*4 = 0.0001 (given)
Lower limit has to be less than 0.0001 because we are dividing by 4
So we can reject A(0.0025>0.0001) & B(0.00025>0.0001)
Instead of dividing, I multiplied lower limit of C to avoid error in decimals
0.000025*4 = 0.0001 (given)
21 Oct 2024, 23:20
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Solution:
The sequence is such that each term is half of the previous term. Let the first term be "a".
• The second term is a/2, the third term is a/4, and so on.
• The general term for the sequence is: a * (1/2)^(n-1), where "n" is the term number.
The tenth term is between 0.0001 and 0.001, so: a * (1/2)^9 is between 0.0001 and 0.001.
For the twelfth term: a * (1/2)^11 = (1/4) * a * (1/2)^9
This means the twelfth term is 1/4 of the tenth term, which is between 0.0001 and 0.001.
So, the twelfth term is between: 0.0001 / 4 = 0.000025 and 0.001 / 4 = 0.00025.
Answer:
(C) 0.000025 and 0.00025
The sequence is such that each term is half of the previous term. Let the first term be "a".
• The second term is a/2, the third term is a/4, and so on.
• The general term for the sequence is: a * (1/2)^(n-1), where "n" is the term number.
The tenth term is between 0.0001 and 0.001, so: a * (1/2)^9 is between 0.0001 and 0.001.
For the twelfth term: a * (1/2)^11 = (1/4) * a * (1/2)^9
This means the twelfth term is 1/4 of the tenth term, which is between 0.0001 and 0.001.
So, the twelfth term is between: 0.0001 / 4 = 0.000025 and 0.001 / 4 = 0.00025.
Answer:
(C) 0.000025 and 0.00025
