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# In a certain town, the ratio of the number of rented residences to the

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Re: In a certain town, the ratio of the number of rented residences to the [#permalink]
Bunuel wrote:
In a certain town, the ratio of the number of rented residences to the number of owned residences is 7:4. Those are the only two kinds of residences in this town. If there are 150 more rented than owned residences in this town, what is the total number of residences in the town?

A. 200
B. 350
C. 550
D. 700
E. 1100

$$Rented = r$$; and $$Owned = w$$

$$\frac{r}{w}=\frac{7}{4}$$ and $$r=w + 150$$;

$$\frac{r}{w}=\frac{(w + 150)}{w}=\frac{7}{4};(w + 150)*4=7w;4w+600=7w;600=3w;w=200$$

$$r = w + 150;r = (200)+150 = 350$$

$$Total = w+r=(350)+(200)=550$$

(C) is the answer.
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In a certain town, the ratio of the number of rented residences to the [#permalink]
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Bunuel wrote:
In a certain town, the ratio of the number of rented residences to the number of owned residences is 7:4. Those are the only two kinds of residences in this town. If there are 150 more rented than owned residences in this town, what is the total number of residences in the town?

A. 200
B. 350
C. 550
D. 700
E. 1100

May be a slightly easier and faster approach..

Ratio 7:4, so numbers can be 7x and 4x.. total = 11x
your answer in form 11x means a MULTIPLE of 11... ONLY C and E

difference = $$7x-4x=3x=150.....x=\frac{150}{3}=50$$..
so total = $$11x=11*50=550$$

C
In a certain town, the ratio of the number of rented residences to the [#permalink]
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