andreasonlinegr wrote:

In a certain two-digit integer , the ration of the units digit to the tens digit is 2 to 3. what is the integer?

1) the tens digit is 3 more than the units digit

2) the product of the two digits is 54.

Answer is E.

Please help solve this.

a+10b , 10b/a = 2/3 thus

30b = 2a ie: 15b = a rewriting the number : 15b+10b = 25b

from 1

a= 3+b....insuff ( we need b)

from 2

ab = 54 = 2*3^3 ......insuff( multiple values)

both

3b+b^2 = 54 thus b^2+3b+54v= 0

(b+6)(b+9) = 0 thus b could be either -6 or -9...insuff

E