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26 Sep 2019, 04:29
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
30% (02:14) correct
70%
(01:21)
wrong
based on 110
sessions
History
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Not Attempted Yet
In a city, only two leaders X and Y contested. The number of valid votes is 300. Who won the election?
(1) Among the voters, whose votes are valid. 79% of the male voters and 43 % of the female voters voted in favour of X
(2) The ratio of male to female in the city is 2:1
(1) Among the voters, whose votes are valid. 79% of the male voters and 43 % of the female voters voted in favour of X
(2) The ratio of male to female in the city is 2:1
26 Sep 2019, 18:50
Kudos
Bookmarks
Total number of votes=300
1) Number of males=x
number of females= 300-x
Number of male voters voted for X= \(\frac{79}{100} *x\)
\(\frac{79}{100} *x\) is an integer; Hence, x must be a multiple of 100
Case 1- when x=100
male voters voted X=79
female voters voted X= 2*43=86
Total number of votes to X=79+86=165>150
Case 2- when x=200
male voters voted X=79*2= 158
female voters voted X= 43
Total number of votes to X=158+43=201>150
In both cases X wins
Sufficient
Statement 2- Clearly insufficient
A
1) Number of males=x
number of females= 300-x
Number of male voters voted for X= \(\frac{79}{100} *x\)
\(\frac{79}{100} *x\) is an integer; Hence, x must be a multiple of 100
Case 1- when x=100
male voters voted X=79
female voters voted X= 2*43=86
Total number of votes to X=79+86=165>150
Case 2- when x=200
male voters voted X=79*2= 158
female voters voted X= 43
Total number of votes to X=158+43=201>150
In both cases X wins
Sufficient
Statement 2- Clearly insufficient
A
Bunuel
26 Sep 2019, 19:46
Kudos
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Bunuel
(1) Among the voters, whose votes are valid. 79% of the male voters and 43 % of the female voters voted in favour of X
Now, what should strike you is that 79 and 43 are primes, and looking at prime numbers should force you to go a bit deeper into the solution..
The number would always be an integer, and SO when would 79% be an integer?-- When the total is a multiple of 100.
I. If males are 100 and females are 200...votes x got =\(\frac{79}{100}*100+\frac{43}{100}*200=79+2*43=165\)
II. If males are 200 and females are 100...votes x got = \(\frac{79}{100}*200+\frac{43}{100}*100=79*2+43\)
III. It is not possible that ONLY females are there or ONLY males are there, since then 79% of MALE and 43% of FEMALE does not stand.
So, in each case X wins the election
Suff
(2) The ratio of male to female in the city is 2:1
The answer could be anything, as we do not know the pattern of how males and females have voted.
Insuff
A
