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In a class, 60% of students play soccer or basketball. If 10% play bot
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21 Sep 2020, 04:00
21 Sep 2020, 04:00
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A
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Difficulty:
75%
(hard)
Question Stats:
54% (01:59) correct
46%
(02:00)
wrong
based on 200
sessions
In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays basketball only?
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
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Re: In a class, 60% of students play soccer or basketball. If 10% play bot
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21 Sep 2020, 05:39
21 Sep 2020, 05:39
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Let Total no. of students = 100
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
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Re: In a class, 60% of students play soccer or basketball. If 10% play bot
[#permalink]
11 Oct 2020, 03:38
11 Oct 2020, 03:38
Let the total number of students be 100.
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
