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20 Jun 2019, 19:35
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In a class, if 60% of the boys were girls, then there would be 100% more girls than boys. What percentage of the overall class is girls?
A. 25%
B. 33.33%
C. 40%
D. 20%
E. 16.66%
A. 25%
B. 33.33%
C. 40%
D. 20%
E. 16.66%
20 Jun 2019, 20:45
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Dillesh4096
In a class, if 60% of the boys were girls, then there would be 100% more girls than boys. What percentage of the overall class is girls?
A. 25%
B. 33.33%
C. 40%
D. 20%
E. 16.66%
Posted from my mobile device
A. 25%
B. 33.33%
C. 40%
D. 20%
E. 16.66%
Posted from my mobile device
Percentage problem:- take the number to be 100.
Take boys to be 100, so if 60% were girls, only 40 are boys.
Also, girls are 100% of boys now, so 40+40=80.
Total strength =40+80=120.
Actual strength of girls =120-actual strength of boys=120-100=20.
As a %, girls are \(100*\frac{20}{120}\)=16.66%
E
globaldesi
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20 Jun 2019, 21:42
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Let the total number of boys be "b" and total number of girls be "g"
given
\(2*(.4b)= g+.6b\)
thus
\(.8b -.6b = g\)
or \(\frac{b}{5}= g\)
now asked in question:
\(\frac{g}{(g+b)} *100\)
\(\frac{g}{(5g+g)}*100\)
\(1/6*100\)
= 16.666%
given
\(2*(.4b)= g+.6b\)
thus
\(.8b -.6b = g\)
or \(\frac{b}{5}= g\)
now asked in question:
\(\frac{g}{(g+b)} *100\)
\(\frac{g}{(5g+g)}*100\)
\(1/6*100\)
= 16.666%
