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In a convenience store in a certain year, the average (arithmetic mean

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In a convenience store in a certain year, the average (arithmetic mean  [#permalink]

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New post 14 Mar 2018, 01:27
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Question Stats:

32% (01:43) correct 68% (02:03) wrong based on 24 sessions

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In a convenience store in a certain year, the average (arithmetic mean) monthly sales of soda X was n dollars. Was this less than, greater than, or equal to the average (arithmetic mean) monthly sales of soda Y, in dollars?

(1) The average (arithmetic mean) monthly sales of soda Y from January to August were n dollars.

(2) The average (arithmetic mean) monthly sales of soda Y from May to December were 2n dollars.

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Re: In a convenience store in a certain year, the average (arithmetic mean  [#permalink]

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New post 14 Mar 2018, 01:47
Bunuel wrote:
In a convenience store in a certain year, the average (arithmetic mean) monthly sales of soda X was n dollars. Was this less than, greater than, or equal to the average (arithmetic mean) monthly sales of soda Y, in dollars?

(1) The average (arithmetic mean) monthly sales of soda Y from January to August were n dollars.

(2) The average (arithmetic mean) monthly sales of soda Y from May to December were 2n dollars.


IMO B.

Question -> average monthly sales of soda X was n dollars.

Statement 1. average for 8 months (Jan to aug) was n dollars. Depending on whether the next 4 months give a better or worse average than n... the overall average of soda Y could be higher or lesser or equal to n.

Not sufficient.

Statement 2. average for 8 months ( May to Dec) was 2n dollars. hence the total sales for these 8 months is already 8*2n = 16n dollars.
The average for 12 months will be (total for 12 months) / 12.

Hence ( 16n + positive or zero ) /12 > n

Which is sufficient.

Hence B.
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Re: In a convenience store in a certain year, the average (arithmetic mean   [#permalink] 14 Mar 2018, 01:47
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