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18 Jan 2024, 02:30
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A
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Difficulty:
35%
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Question Stats:
66% (01:15) correct
34%
(01:26)
wrong
based on 68
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In a fruit store, apples are priced at $4 per pound and oranges at $6 per pound. Was the total weight of apples sold more than the total weight of oranges sold?
(1) The average (arithmetic mean) price per pound of the fruit sold is less than $5.
(2) The total weight of all the fruit sold is 10 pounds.
(1) The average (arithmetic mean) price per pound of the fruit sold is less than $5.
(2) The total weight of all the fruit sold is 10 pounds.
At a fruit store, apples are sold for $4 per pound and oranges are sold for $6 per pound. Is the total weight of apples sold greater than the total weight of oranges sold?
1) The average (arithmetic mean) price of fruit sold is less than $5.
2) The total weight of fruit sold is 10 pounds.
1) The average (arithmetic mean) price of fruit sold is less than $5.
2) The total weight of fruit sold is 10 pounds.
19 Jan 2024, 02:20
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IMO - A
the average would be 5 if we sold the same amount of apples as oranges. Average= (4$*A + 6$*O)/(A + O)
1. sufficient, because the average is below 5 we must have sold more of the cheaper good, thus A.
2. not sufficient, because there are no restrictions given to decide what part is due to sold apples and what is due to sold oranges
the average would be 5 if we sold the same amount of apples as oranges. Average= (4$*A + 6$*O)/(A + O)
1. sufficient, because the average is below 5 we must have sold more of the cheaper good, thus A.
2. not sufficient, because there are no restrictions given to decide what part is due to sold apples and what is due to sold oranges
Aryaa03
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19 Jan 2024, 08:04
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Bunuel
Sol: Option-A
Apples are priced at $4 per pound and Oranges at $6 per pound;
Let, A be the weight of apples sold in pounds and O be the weight of oranges sold in pounds;
Asked: Is A > O
St-1:
The average (arithmetic mean) price per pound of the fruit sold is less than $5.
Average (arithmetic mean) price per pound of the fruit sold = Total amount of fruits sold in Dollar / Total weight in Pounds < 5
===> (4*A + 6*O) / (A + O) < 5
4*A/(A+O) + 6*O/(A+O) < 5
If A had been equal to O , the average would have been 5 as A/(A+O) = O/(A+O) = 1/2
As the average is below the midpoint of 4 & 6, ==> weightage of A is more than O ; Hence, A > O
Statement is Sufficient
St-2:
The total weight of all the fruit sold is 10 pounds.
A + O = 10
This statement is clearly Insufficient
