|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
13 Mar 2004, 16:24
Kudos
Bookmarks
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
(N/A)
Question Stats:
0% (00:00) correct
0%
(00:00)
wrong
based on 0
sessions
History
Date
Time
Result
Not Attempted Yet
In a kilometre race, A gives B a start of 50 metres and still beats him by 50 metres. On the other hand, if A gives B a start of 20 seconds, he beats him by 5 seconds. How long does A take to run the course?
250 seconds
200
180
225
None of the above
250 seconds
200
180
225
None of the above
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
14 Mar 2004, 12:09
Kudos
Bookmarks
I will go for d i.e 225.
1. Let the speed of A be 'a' m/s.
2. B covers 900 m when A covers 1000 m.(from 1st statement of ques.)
3. From 1 and 2. Speed of B = (9a/10) m/s.
4. Time taken by B = (1000)/(9a/10) = 10000/9a seconds(using 3)
5. Time taken by A = (time taken by B - 25) seconds (using statement 2 of question)
= ((10000/9a) - 25) seconds
6. Time taken by A is also equal to 1000/a seconds
7. Equating 6 and 7, we get
Speed of A = a= 40/9 m/s
8. Thus time taken by a = (1000)/(40/9) = 25*9 = 225 seconds.
cheers
1. Let the speed of A be 'a' m/s.
2. B covers 900 m when A covers 1000 m.(from 1st statement of ques.)
3. From 1 and 2. Speed of B = (9a/10) m/s.
4. Time taken by B = (1000)/(9a/10) = 10000/9a seconds(using 3)
5. Time taken by A = (time taken by B - 25) seconds (using statement 2 of question)
= ((10000/9a) - 25) seconds
6. Time taken by A is also equal to 1000/a seconds
7. Equating 6 and 7, we get
Speed of A = a= 40/9 m/s
8. Thus time taken by a = (1000)/(40/9) = 25*9 = 225 seconds.
cheers
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
