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Bunuel
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Bunuel
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YUKESH23
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Similar tricky question to practice: https://gmatclub.com/forum/in-a-factory ... 44378.html
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Anyone else want to try this question?
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Bunuel
Anyone else want to try this question?
Rate for 24 printers is 2/9 and in 2.5 hours they complete 5/9 work, in additional 1.5 hours they complete a total of 8/9 of work.
Now we need to know if the reserve printers can complete this 1/9 work within the 1.5 hours.

Using Statement 1 we can directly get rate of reserve printers and hence it's sufficient

Statement 2 on the other hand says rate of 1 reserve printer is less than 1 regular printer. However if it was greater we could've said with gurantee that 1/9th of work would've finished within 1.5 hours (24 regular printers finish 3/9 work in 1.5 hours) but since its less we don't know how much exactly less.

Hence option A
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If 36 printers do the job in 3 hours, we have: 36*3*1/x=N, where 1/x is the rate and N is the total amount of newspapers. After simplification, we obtain that the rate = N/108.


If we follow the problem, we have the following equation: 2.5*24*N/108 + t*24*N/108 + 48*t*x = N, where t is the time after 2.5 hours and x is the rate of the reserve printer.

After algebraic manipulations, we will obtain: t = 4N / (2N + 48*x*9).

Now we can see the conditions:

1) If we know how N and x are related, the problem would be a linear one-variable problem. Hence, A on its own is enough.

2) If we know that x is less than N/108, we can substitute the maximum and minimum values into x. Min value would be close to zero and in that case t = 2 that is more than 1.5. However, if we substitute close to N/108 the time would be close to 2/3, which is less than 1.5. Hence, B is not our answer.
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