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30 Oct 2019, 02:56
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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84% (00:57) correct
16%
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In a right isosceles triangle, the lengths of the two nonhypotenuse sides are designated a. What is the area of the triangle in terms of a?
A. 1/3*a^2
B. \(\frac{\sqrt{2}}{3}*a^2\)
C. 1/2*a^2
D. \(\frac{\sqrt{3}}{2}*a^2\)
E. \(\sqrt{2}a^2\)
A. 1/3*a^2
B. \(\frac{\sqrt{2}}{3}*a^2\)
C. 1/2*a^2
D. \(\frac{\sqrt{3}}{2}*a^2\)
E. \(\sqrt{2}a^2\)
30 Oct 2019, 03:10
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Let ABC be an Isosceles Right triangle with Angle(B) =90 deg
Then by the given data AB = BC = non-hypotenuse sides = 'a' and AC= Hypotenuse
Area of a right triangle = 1/2*base*height
Here the base = height = 'a'
Therefore, Area = (1/2)*a*a = (1/2)a^2
Ans: C
Then by the given data AB = BC = non-hypotenuse sides = 'a' and AC= Hypotenuse
Area of a right triangle = 1/2*base*height
Here the base = height = 'a'
Therefore, Area = (1/2)*a*a = (1/2)a^2
Ans: C
30 Oct 2019, 09:38
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Given is Base(a) and Height(a) of a right angled isosceles triangle.
\(Area = \frac{1}{2}*base*height => \frac{1}{2}* a * a\)
IMO Answer is Option C!
\(Area = \frac{1}{2}*base*height => \frac{1}{2}* a * a\)
IMO Answer is Option C!
