say,team 1 =T1 and team2 =T2
like this we have T3,T4,T5,T6
EACH TEAM CONSISTS OF 4 MEMBERS, SO 6 SEATS ARE REMAINING EMPTY.
and each empty seat = E
ultimately question becomes in how many different way you can arrange T1,T2,T3,T4,T5,T6,E,E,E,E,E,E
= \(12!/6!\)
note- you do not need to multiple by 4! to arrange members of each team as question has clearly stated.
Quote:
The members of any one team always sit together in four consecutive seats in the same order.
_________________
It’s not that I’m so smart, it’s just that I stay with problems longer. -- Albert Einstein