Solution

• In a sequence, all the terms are arranged in decreasing order of value
• The difference between any two consecutive terms is equal to 4.
• The number of terms in the sequence is odd, and
• The sum of first term and last term is zero

• The sum of all terms in the sequence

• Let the terms in the sequence be: a, a – d, a – 2d, a – 3d, …., a + (n – 1) * d, where d = 4
• We are given that,

o a + a + (n – 1) * 4 = 0
o Implies. 2a + 4(n – 1) = 0


• Sum of all terms = \([2a + (n – 1) * 4] * \frac{n}{2} = 0 * \frac{n}{2} = 0\)

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