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Given that the sequence is defined as:

m(n+1) = 3mn + 2, n ≥ 1 and m1 = 3

We can calculate m4 and m6 as follows:

m2 = 3m1 + 2 = 3(3) + 2 = 11
m3 = 3m2 + 2 = 3(11) + 2 = 35
m4 = 3m3 + 2 = 3(35) + 2 = 107

m5 = 3m4 + 2 = 3(107) + 2 = 323
m6 = 3m5 + 2 = 3(323) + 2 = 966+2 = 971

Therefore, the corresponding values of m4 and m6 are:

m4 = 107
m6 = 971
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