Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
15 May 2020, 09:28
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
65% (02:52) correct
35%
(02:36)
wrong
based on 127
sessions
History
Date
Time
Result
Not Attempted Yet
In a sequence of numbers in which the difference of any two successive terms is k, the sum of the first 25 terms is 525 and the sum of the next 25 terms is 725. What is the value of k?
A. 1/25
B. 2/25
C. 3/25
D. 4/25
E. 8/25
A. 1/25
B. 2/25
C. 3/25
D. 4/25
E. 8/25
15 May 2020, 19:41
Kudos
Bookmarks
In a sequence of numbers in which the difference of any two successive terms is k, the sum of the first 25 terms is 525 and the sum of the next 25 terms is 725. What is the value of k?
Tn = a + (n - 1) d, where Tn = nth term and a = first term. Here d = common difference = Tn - Tn-1.
Sn =(n/2)[2a + (n- 1)d]
S25=25/2[2a+24d]=525
or,a+12d=21
or,2a+24d=42 ---(1)
S50=50/2[2a+49d]=525+725=1250
or,2a+49d=50 ---(2)
(2)-(1)
5d=8
or,d=8/25
in this problem, d=k
so,k=8/25
correct answer E
Tn = a + (n - 1) d, where Tn = nth term and a = first term. Here d = common difference = Tn - Tn-1.
Sn =(n/2)[2a + (n- 1)d]
S25=25/2[2a+24d]=525
or,a+12d=21
or,2a+24d=42 ---(1)
S50=50/2[2a+49d]=525+725=1250
or,2a+49d=50 ---(2)
(2)-(1)
5d=8
or,d=8/25
in this problem, d=k
so,k=8/25
correct answer E
16 May 2020, 08:24
Kudos
Bookmarks
Bunuel
If we label the terms with \(a(n)\), we can compare the sum of \(a(1) + a(2) + ... + a(25)\) and \(a(26) + a(27) + ... a(50) \)and focus on the each term in comparison.
\(a(26)\) is bigger than \(a(1)\) by \(25k\), \(a(27)\) is bigger than \(a(2)\) by \(25k\) etc, then the entire latter sum would be \(25 * 25k = 625k\) bigger.
The actual difference is \(725 - 525 = 200\) however so \(200 = 625k\), \(k = 8/25\).
Ans: E
