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In a series of eight consecutive integers, the third term is 7. What

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In a series of eight consecutive integers, the third term is 7. What  [#permalink]

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New post 23 Jan 2019, 01:13
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94% (00:57) correct 6% (00:57) wrong based on 22 sessions

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In a series of eight consecutive integers, the third term is 7. What  [#permalink]

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New post Updated on: 24 Jan 2019, 08:41
IMO D
7 is the third consecutive term of the series thereby the series should be as under
5,6,7,8,9,10,11,12
Sum of 8 terms of this series = 68

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Originally posted by carajatarora on 23 Jan 2019, 01:21.
Last edited by carajatarora on 24 Jan 2019, 08:41, edited 1 time in total.
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Re: In a series of eight consecutive integers, the third term is 7. What  [#permalink]

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New post 23 Jan 2019, 06:56
Bunuel wrote:
In a series of eight consecutive integers, the third term is 7. What is the sum of the eight integers?


A 42
B 56
C 64
D 68
E 72


for 7 consective terms = 8x+28
third term = x+2
x+2= 7
x= 5
so sum
40+ 28 = 68
IMO D
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Re: In a series of eight consecutive integers, the third term is 7. What  [#permalink]

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New post 23 Jan 2019, 14:48
Bunuel wrote:
In a series of eight consecutive integers, the third term is 7. What is the sum of the eight integers?


A 42
B 56
C 64
D 68
E 72


mean=7+1+.5=8.5
sum=8.5*8=68
D
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Re: In a series of eight consecutive integers, the third term is 7. What   [#permalink] 23 Jan 2019, 14:48
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In a series of eight consecutive integers, the third term is 7. What

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