capsicumgirl wrote:
In a set of three numbers,the difference between the largest and the second largest numbers is added to the smallest number.The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 5.The largest number exceeds the second largest number by how much ?
A) 5
B) 10
C) 15
D) 30
E) 60
Let A,B and C be the three numbers where A<B<C
It is given that the difference between the largest and the second largest numbers is added to the smallest number i.e A+(C-B)
The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 5.
or \(\frac{B+C+A+(C-B)}{3}=\frac{A+B+C}{3}+5\)
or \(\frac{A+2C}{3}=\frac{A+B+C+15}{3}\)
or \(A+2C=A+B+C+15\)
or \(C=B+15\)
So, largest number exceeds the second largest number by 15
Answer:-C