Poots wrote:

In a survey of 248 people, 156 are married, 70 are self-employed, and 25 percent of those who are married are self-employed. If a person is to be randomly selected from those surveyed, what is the probability that the person selected will be self-employed but not married?

a. 1/8

b. 4/31

c. 117/248

d. ¼

e. 31/117

Thanks.

we see that clearly ,1/4*156 =39 people are both maried and self-emp.

hence 70-39=31 are those who are self-emp and not married

also total of 248 people exit ,one needs to be picked from the same

hence prob that self-emp not married = 31/248=1/8

IMO A

OA plsss

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cheers

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