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12 Jul 2019, 07:34
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm, then what is the radius (in cm) of the circle circumscribing the triangle ABC?
(1) 17.05
(2) 27.85
(3) 22.45
(4) 32.25
(5) 26.25
(1) 17.05
(2) 27.85
(3) 22.45
(4) 32.25
(5) 26.25
WiziusCareers1
Joined: 27 Apr 2009
Last visit: 15 Dec 2024
Posts: 116
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Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
13 Jul 2019, 01:59
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Note: This is definitely not a GMAT Question
Radius of the circumscribing circle = (AB * BC * CA)/(4 * Area of the triangle)
Area of the triangle = 1/2 * (AD * BC)
=> (AB * BC * CA)/(4 * Area of the triangle) = (AB * BC * CA)/(4 * 1/2 * AD * BC)
= (AB * CA)/(2 * AD)
= (17.5 * 9)/(2 * 3) = 26.25
The answer is (E).
Radius of the circumscribing circle = (AB * BC * CA)/(4 * Area of the triangle)
Area of the triangle = 1/2 * (AD * BC)
=> (AB * BC * CA)/(4 * Area of the triangle) = (AB * BC * CA)/(4 * 1/2 * AD * BC)
= (AB * CA)/(2 * AD)
= (17.5 * 9)/(2 * 3) = 26.25
The answer is (E).
