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In an apartment building that has 490 units, 4 out of every [#permalink]

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02 Jul 2013, 23:23

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In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented? (A) 50 (B) 70 (C) 100 (D) 105 (E) 140

Re: In an apartment building that has 490 units, 4 out of every [#permalink]

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02 Jul 2013, 23:38

vtran wrote:

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?

(A) 50 (B) 70 (C) 100 (D) 105 (E) 140

Kudos if you find it useful! Thanks!

Out of every 7 units, 4 are rented. Thus, out of 490 units, \(4*\frac{490}{7}\) will be rented \(\to 280\). Total no of not rented bedrooms = (490-280)= 210 units.

Let the total no of 1 bedroom units be 5x.The total rented apartments include x units of 1 bedroom and 6x units of 2 bedrooms \(\to 7x\) = \(280 \to x\)= 40. Thus, the total no of 1 bedroom units = 5*40 = 200. Total not rented 1 bedroom units = (200-40)=160 The no of 2 bedroom units not rented = 210-160= 50 units. A.
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Re: In an apartment building that has 490 units, 4 out of every [#permalink]

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02 Apr 2015, 05:48

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Re: In an apartment building that has 490 units, 4 out of every [#permalink]

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17 Aug 2017, 12:52

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: In an apartment building that has 490 units, 4 out of every [#permalink]

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17 Aug 2017, 19:48

Bunuel wrote:

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented? (A) 50 (B) 70 (C) 100 (D) 105 (E) 140

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented? (A) 50 (B) 70 (C) 100 (D) 105 (E) 140

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?

(A) 50 (B) 70 (C) 100 (D) 105 (E) 140

Since 4 out of 7 apartments in the building are rented out, the number of apartments rented out is (4/7)(490) = 280.

We can let the ratio of two-bedroom units to one-bedroom units = 6x : x; thus, the total number of rented apartments is 7x and we can create the following equation:

7x = 280

x = 40

Thus, we have 6(40) = 240 two-bedroom apartments and 40 one-bedroom apartments that are rented out.

Since the 40 one-bedroom apartments that are rented out represent 1/5 of all the one-bedroom apartments in the building, the number of one-bedroom apartments in the building is 40/(1/5) = 200. Thus, there are 490 - 200 = 290 two-bedroom apartments in the building. Finally, since 240 two-bedroom apartments are rented out, 290 - 240 = 50 two-bedroom apartments are not rented out.

Answer: A
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Re: In an apartment building that has 490 units, 4 out of every [#permalink]

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23 Aug 2017, 00:09

vtran wrote:

In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?

(A) 50 (B) 70 (C) 100 (D) 105 (E) 140

Kudos if you find it useful! Thanks!

Total units = 490

Total rented = 4/7(490)=280

given ratio of 2br:1br=6:1

Hence total 2 br rented = 6/7(280)=240

Given 1/5(1BR)=40 (Total rented-2Br rented) hence Total 1BR=200 Total Units - Total 1BR = Total 2BR 490-200=290= Total 2BR unrented 2BR = 290-240(Rented 2BR) Hence answer is 50. Option A

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