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# In an election contested by two parties, Party D secured 12% of the to

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Math Expert
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In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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15 Mar 2016, 12:45
12
00:00

Difficulty:

65% (hard)

Question Stats:

68% (02:56) correct 32% (02:53) wrong based on 138 sessions

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In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

A. 24,000
B. 36,000
C. 168,000
D. 240,000
E. 300,000

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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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15 Mar 2016, 19:00
4
1
D + R = 100 ---- (1)
D - R = 12 ---- (2)
Solving (1) and (2) D = 56% and R = 44%
44% of Total = 132000
Total = 300000

D = 168000

Difference = 168000 - 132000 = 36000

##### General Discussion
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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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19 Mar 2016, 10:39
Hi Vyshak,

Is there an alternative way to solve this problem? I'm also having trouble completing this problem quickly - going from 132,000 = (44/100)*x to finding the value of X.
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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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19 Mar 2016, 10:58
Wilfy wrote:
Hi Vyshak,

Is there an alternative way to solve this problem? I'm also having trouble completing this problem quickly - going from 132,000 = (44/100)*x to finding the value of X.

Hi Wilfy,

I do not know an alternate way to solve this problem without having any calculations. But, whenever there are 0's involved in the calculation, you can remove the zeros temporarily and append zeros after the calculation is completed. Here we can consider: 132 = 44 * x. So, x = 3. We can append 5 zeros after completing this small calculation.
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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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13 Apr 2016, 09:20
very confusing language used in this question..
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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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12 Apr 2018, 16:19
1
Bunuel wrote:
In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

A. 24,000
B. 36,000
C. 168,000
D. 240,000
E. 300,000

We can let x = the percent of votes Party R got, and so (x + 12) = the percent of votes Party D got. We can create the equation:

x + x + 12 = 100

2x = 88

x = 44

Thus Party R got 44 percent of the votes and we are given that Party R got 132,000 votes. We can create the equation where n = the total number of votes:

0.44n = 132,000

44n = 13,200,000

n = 300,000

Since the total number of votes is 300,000, and Party R lost by 12% of the total votes, thus Party R lost by

0.12 x 300,000 = 36,000 votes

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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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23 Apr 2018, 02:47
Vyshak wrote:
D + R = 100 ---- (1)
D - R = 12 ---- (2)
Solving (1) and (2) D = 56% and R = 44%
44% of Total = 132000
Total = 300000

D = 168000

Difference = 168000 - 132000 = 36000

Superb approach to solve the question.. I think we can't shorten the approach.. Its flawless..
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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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23 Apr 2018, 02:52
Bunuel wrote:
In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

A. 24,000
B. 36,000
C. 168,000
D. 240,000
E. 300,000

Sum of percentage of votes of D & R = 100%
So, D+ R = 100

Difference of percentage of votes of D & R = 12% ( D being greater than R )
D-R = 12

2D = 112
D= 56%

R = 44%

Now 44% of T = 132k
T = 132k/.44

So, R lost by 132k/.44 * .12 = 132k/.11 * 0.03 = 132k*3/11 = 12k * 3 = 36k = 36,000

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Re: In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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04 Jun 2018, 03:47
Bunuel wrote:
In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

A. 24,000
B. 36,000
C. 168,000
D. 240,000
E. 300,000

Given: Party D secured 12% of the total votes more than Party R
Hence Party R secured = $$\frac{(100-12)}{2}$$=44% votes.

Now 44% votes represent $$132,000$$ votes in number.
Thus 12% represents = $$\frac{132000}{44}$$*$$12$$=$$36,000$$ votes in number.
Hence I would go for option B.
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In an election contested by two parties, Party D secured 12% of the to  [#permalink]

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06 Aug 2018, 14:56
Let x be the total no of votes,

then,

Thus votes gained by winning party = x-132,000. ------------(1)

But we also know,
votes gained by winning party = 132000 +12%of Total votes = 132000 +$$\frac{12}{100}$$ *x ------------(2)

Equate (1) and (2)

x-132,000 = 132000 + $$\frac{12}{100}$$*x
Solving for x, we get,
x = 300,000 which is the total no of votes.
12% of x = 36000.

Option B.
In an election contested by two parties, Party D secured 12% of the to   [#permalink] 06 Aug 2018, 14:56
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