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In an election with only two candidates, before absentee

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In an election with only two candidates, before absentee  [#permalink]

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New post 23 Mar 2011, 07:42
4
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

59% (02:07) correct 41% (02:31) wrong based on 141 sessions

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In an election with only two candidates, before absentee ballots were counted candidate Jones received a votes and candidate Smith received b votes. If 900,000 non-absentee votes were cast, what was the percent change in the number of votes after the counting of absentee ballots?

(1) Candidate Jones received 43% of the votes cast before absentee ballots were counted and received 43% after absentee ballots were counted.
(2) Candidate Smith received 57% of the votes cast both before and after absentee ballots were counted and received 387,000 votes after absentee ballots were counted.

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Re: average ds  [#permalink]

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New post 23 Mar 2011, 08:14
rxs0005 wrote:
In an election with only two candidates, before absentee ballots were counted candidate Jones received a votes and candidate Smith received b votes. If 900,000 non-absentee votes were cast, what was the percent change in the number of votes after the counting of absentee ballots?

(1) Candidate Jones received 43% of the votes cast before absentee ballots were counted and received 43% after absentee ballots were counted.
(2) Candidate Smith received 57% of the votes cast both before and after absentee ballots were counted and received 387,000 votes after absentee ballots were counted.


I usually reduce the numbers by dividing the number with 1000.

Total - 900 non-absentee votes
Let the absentee votes be "x"

a+b=900

Q: [x/900]*100
Or what is x?

1.
a = 0.43*900 = 387
After x votes added;
Jones received 0.43*x
We won't know x by this information.
Not Sufficient.

(2) Candidate Smith received 57% of the votes cast both before and after absentee ballots were counted and received 387,000 votes after absentee ballots were counted.

b=0.57*900=513
0.57*x=387

x is found.
Sufficient.

Ans: "B"
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Re: average ds  [#permalink]

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New post Updated on: 23 Mar 2011, 17:25
Fluke!
I think you assumed 57% of total as 57% of total as 57% of 900 & 57% absentee ballots. However i think it is
57%(900+x) = b + 387
so we can have many values of X and b that still satisfies the equation.
So statement 2 is not sufficient.

I think we need statement 1 to verify that 57% was alone for 900 as well. As statement 1 states "Jones received 43% of the votes cast before absentee ballots were counted" . Therefore Smith received 57% before absentee ballots were counted.
Then we can move into your calculation, which is correct.
But Answer should be C.

Correct me if I am wrong.
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Originally posted by bhandariavi on 23 Mar 2011, 17:20.
Last edited by bhandariavi on 23 Mar 2011, 17:25, edited 1 time in total.
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Re: average ds  [#permalink]

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New post 23 Mar 2011, 17:22
1
a+b votes - before absentee ballots were counted

a+b + 900000 votes - after non-absentee ballots were counted

So -> 900000/(a+b) * 100 = ?

(1)

Jones - 43/100(a + b) - Before Absentee ballots

And again Jones - 43/100(900000 + a+b) - After Absentee ballots

But this is not sufficient.

(2)

Smith - 57/100(a+b) - Before Absentee ballots

387000 = 57/100(a+b + 900000), so a+b can be calculated from this, and then 900000/(a+b) * 100 also can be calculated.

Answer - B
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Re: average ds  [#permalink]

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New post 23 Mar 2011, 21:14
bhandariavi wrote:
Fluke!
I think you assumed 57% of total as 57% of total as 57% of 900 & 57% absentee ballots. However i think it is
57%(900+x) = b + 387
so we can have many values of X and b that still satisfies the equation.
So statement 2 is not sufficient.

I think we need statement 1 to verify that 57% was alone for 900 as well. As statement 1 states "Jones received 43% of the votes cast before absentee ballots were counted" . Therefore Smith received 57% before absentee ballots were counted.
Then we can move into your calculation, which is correct.
But Answer should be C.

Correct me if I am wrong.


You wrote the same equation I did.
57%(900+x) = b + 387
i.e.
57%(900)+(57%)x=b+387

It is given that b=(57%)*900= 513
It means that out of 900 non-absentee ballots, Smith received 513 votes(this info is not required to answer the question though)

After the absentee ballot were counted, Smith received 57% as well. Means, out of the total count of absentee ballots, Smith's votes were 57%.

If 'x' absentee ballots were counted, Smith's votes were 57% of x and it is given that it equated to 387
i.e.
57% of x=387
x= 678.something(i see that it is a decimal, which is wrong)

Well!!! if we ignore that, we will get x=678

And percentage change in votes = (678/900)*100 = 77.something%

I think we need statement 1 to verify that 57% was alone for 900 as well. As statement 1 states "Jones received 43% of the votes cast before absentee ballots were counted"

We know this info from 2 itself; the question states "In an election with only two candidates". However, I don't think that's even required.

We knew 900 were non-absentee ballots and we just needed x(count of absentee ballots) to know the % change in votes, which can be derived only from 0.57x=387

The only discrepancy I find the question is that decimal value for "x".

Maybe I am missing something. Please correct me if I have gone wrong anywhere.
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Re: average ds  [#permalink]

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New post 24 Mar 2011, 05:59
You wrote the same equation I did.
57%(900+x) = b + 387
i.e.
57%(900)+(57%)x=b+387

It is given that b=(57%)*900= 513
My only question is highlighted part. I am not sure about the statement 2 Yet. If it means Smith received 57% of total votes then I disagree with your solution because you can't be sure that b= 57% of 900. In the above case try substituting x= 300 and b= 297 , the equation still satisfies.
However, If the statement 2 means Smith received 57% of unabsentee ballots votes and 57% of absentee ballots votes - then i agree with your solution.
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Re: average ds  [#permalink]

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New post 24 Mar 2011, 07:25
bhandariavi wrote:
You wrote the same equation I did.
57%(900+x) = b + 387
i.e.
57%(900)+(57%)x=b+387

It is given that b=(57%)*900= 513
My only question is highlighted part. I am not sure about the statement 2 Yet. If it means Smith received 57% of total votes then I disagree with your solution because you can't be sure that b= 57% of 900. In the above case try substituting x= 300 and b= 297 , the equation still satisfies.
However, If the statement 2 means Smith received 57% of unabsentee ballots votes and 57% of absentee ballots votes - then i agree with your solution.


I will leave it to others.

Anyone?
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Re: average ds  [#permalink]

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New post 29 Mar 2011, 05:52
1
statement 1)
jones received 43% of the votes before the counting of the absentee votes and d same even after the counting the absentee votes.
Now take an example:
suppose u have 100$ in ur wallet. then what %age does 43$ constitute of ur wallet..that is as simple as ABC. now if i add an unknown amount ,say x , in ur wallet then the total amount will be (100+x)$. now if i ask to extract 43% of the amount kept in the wallet; then that 43% will also include the initial 43$ plus part of x$ so that the %age
{[43+(part of x)]/[100+x]} * 100=43/100
now we dont know the part of x. hence data is insufficient coz the principle goes wid the question as well
therefore
43/100=[387+(part of x)]/[900+x]
(part of x) and x is unknown. hence the data is insufficient

statement 2)
smith received 57% of the votes before as well as after the counting of the absentee votes.
also its given that smith received 387 votes after absentee votes were counted

the coloured part has got two meanings that smith got a total of 387 votes after counting the absentee votes or smith got 387 votes after the counting of the absentee votes.
since there are only two candidate and since its initially given that smith got 57% of the total non-absentee votes, then only the latter meaning will be considerd

therefore total votes received by smith were 513+387=900
this 387 is actually = (part of x)
coz the actual no of absentee votes wud b larger than 387.

now,
0.57=[(513+387)/(900+x)]
by this we can easily calculate the value of x.
hence answer is B :lol:

kudo me if u r satisfied wid my response
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Re: average ds  [#permalink]

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New post 29 Mar 2011, 06:16
The question can be rephrased as
What are the absentee votes x?

S1 is very insufficient. There is variable x but no equation.

S2 makes sense here because now I can form equation since 0.57x=387k

Hence sufficient. Hence B

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Re: average ds  [#permalink]

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New post 07 Sep 2011, 02:26
Quote:
In an election with only two candidates, before absentee ballots were counted candidate Jones received a votes and candidate Smith received b votes. If 900,000 non-absentee votes were cast, what was the percent change in the number of votes after the counting of absentee ballots?

(1) Candidate Jones received 43% of the votes cast before absentee ballots were counted and received 43% after absentee ballots were counted.
(2) Candidate Smith received 57% of the votes cast [highlight]both before and after[/highlight] absentee ballots were counted and received 387,000 votes after absentee ballots were counted.


Jones: a
Smith: b
a+b=900 000

Statement 1
a= 43% of 900 000=387 000
387 000 + share of absentee ballots = 43% of total votes(absentee ballots, inclusive)
as we do not know how many absentee ballots has Jones garnered, we can't reach a solution for question.
--> insufficient

Statement 2
b= 57% of 900 000 = 513 000
Add absentee ballots that Smith got --> 513 000 + 387 000 = 900 000
900 000 = 57% of total votes (absentee ballots, inclusive)
we can derive the solution for question from this.
--> sufficient

Answer: B
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Re: In an election with only two candidates, before absentee  [#permalink]

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Re: In an election with only two candidates, before absentee &nbs [#permalink] 13 Sep 2018, 09:48
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