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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # In an Equilateral triangle, 3 coins of radii 1 unit each are kept in

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PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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7 00:00

Difficulty:   55% (hard)

Question Stats: 63% (02:26) correct 37% (02:43) wrong based on 46 sessions

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In an Equilateral triangle, 3 coins of radii 1 unit each are kept in such a way that they touch each other and also the sides of the triangle. What is the area of triangle (in sq. units)?

A. 4+5√2
B. 6+4√3
C. 4+6√3
D. 3+8√3
E. 5+3√2
PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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4
1
The radius of circle is one
The smaller triangle is a right angle triangle with 30, 60 and 90 degree as angle whose sides are x, √3*x, 2x
where x = 1 (on comparing)
therefore √3*x = √3

The Side of triangle = √3 + 2 + √3
=> 2√3 + 2

The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)
=> 4√3 + 6 or 6 + 4√3

VERBAL1 you might be able to understand better with diagram. its pure methodological question.
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##### General Discussion
CrackVerbal Representative G
Affiliations: CrackVerbal
Joined: 03 Oct 2013
Posts: 2013
Location: India
GMAT 1: 780 Q51 V46
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
Top Contributor
In an equilateral triangle of side x, if 3 circles of equal radii are drawn touching each other, then the relation between the side and the radius is given as x = 2r ($$\sqrt{3}$$ + 1)

Here r = 1, therefore the side of the equilateral triangle = 2 * 1 ($$\sqrt{3}$$ + 1) = 2($$\sqrt{3}$$ + 1)

Area of an equilateral triangle = $$\frac{\sqrt{3}}{4}$$ * $$x^{2}$$

Therefore Area = $$\frac{\sqrt{3}}{4}$$ * [$$2(\sqrt{3} + 1)] ^2$$

Area = $$\frac{\sqrt{3}}{4}$$ * 4 * (3 + 2*$$\sqrt{3}$$ + 1)

A = $$\sqrt{3}$$ * (4 + 2 * $$\sqrt{3}$$)

A = 4$$\sqrt{3}$$ + 6

Option B

Arun Kumar
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Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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yashikaaggarwal , Bunuel request you'll to post a simpler solution for this one, please.
Manager  S
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Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
yashikaaggarwal wrote:
The radius of circle is one
The smaller triangle is a right angle triangle with 30, 60 and 90 degree as angle whose sides are x, √3*x, 2x
where x = 1 (on comparing)
therefore √3*x = √3

The Side of triangle = √3 + 2 + √3
=> 2√3 + 2

The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)
=> 4√3 + 6 or 6 + 4√3

VERBAL1 you might be able to understand better with diagram. its pure methodological question.

This is a good explanation!
I'm assuming this is the case just for an equilateral triangle. Right yashikaaggarwal?
PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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KaramveerBakshi wrote:
yashikaaggarwal wrote:
The radius of circle is one
The smaller triangle is a right angle triangle with 30, 60 and 90 degree as angle whose sides are x, √3*x, 2x
where x = 1 (on comparing)
therefore √3*x = √3

The Side of triangle = √3 + 2 + √3
=> 2√3 + 2

The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)
=> 4√3 + 6 or 6 + 4√3

VERBAL1 you might be able to understand better with diagram. its pure methodological question.

This is a good explanation!
I'm assuming this is the case just for an equilateral triangle. Right yashikaaggarwal?

Yes, because the question mention the equilateral triangle only. If it had been scalene or isosceles, it would have become complicated.

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Intern  B
Joined: 27 Aug 2019
Posts: 12
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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Where is the squre from the side?
Can anyone tell me how??

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PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
JHTIPU18 wrote:
Where is the squre from the side?
Can anyone tell me how??

Posted from my mobile device

Your question is not clear. which square? the one with side 1?
I draw that. its not given. but can be inferred.
Intern  B
Joined: 27 Aug 2019
Posts: 12
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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Side Suare from the Area.

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Intern  B
Joined: 27 Aug 2019
Posts: 12
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)

How you find the answer so easily. I can't understand.

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PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
JHTIPU18 wrote:
The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)

How you find the answer so easily. I can't understand.

Posted from my mobile device

√3/4*side^2 is the area of equilateral triangle, I just find the side of triangle and put it into the formula to determine area.
Intern  B
Joined: 27 Aug 2019
Posts: 12
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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√3/4*(2√3 + 2)
=> 4√3 + 6 or 6 + 4√3

How you can get the result? 🤔

Posted from my mobile device
PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
JHTIPU18 wrote:
√3/4*(2√3 + 2)^2
=> 4√3 + 6 or 6 + 4√3

How you can get the result? 🤔

Posted from my mobile device

√3/4*(2√3 + 2)^2
√3/4*(12+4+8√3)
√3/4*(16+8√3)
√3/4*4(4+2√3)
√3*(4+2√3)
=> 4√3 + 6 or 6 + 4√3
Intern  B
Joined: 27 Aug 2019
Posts: 12
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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Thank you so much! Very much appreciate!

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Intern  B
Joined: 07 Aug 2018
Posts: 21
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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CrackVerbalGMAT wrote:
In an equilateral triangle of side x, if 3 circles of equal radii are drawn touching each other, then the relation between the side and the radius is given as x = 2r ($$\sqrt{3}$$ + 1)

Here r = 1, therefore the side of the equilateral triangle = 2 * 1 ($$\sqrt{3}$$ + 1) = 2($$\sqrt{3}$$ + 1)

Area of an equilateral triangle = $$\frac{\sqrt{3}}{4}$$ * $$x^{2}$$

Therefore Area = $$\frac{\sqrt{3}}{4}$$ * [$$2(\sqrt{3} + 1)] ^2$$

Area = $$\frac{\sqrt{3}}{4}$$ * 4 * (3 + 2*$$\sqrt{3}$$ + 1)

A = $$\sqrt{3}$$ * (4 + 2 * $$\sqrt{3}$$)

A = 4$$\sqrt{3}$$ + 6

Option B

Arun Kumar

How is this √3 +1 is coming corresponding to 2r(√3+1)

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PS Forum Moderator P
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Posts: 1500
Location: India
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Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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Shubham1213372 wrote:
CrackVerbalGMAT wrote:
In an equilateral triangle of side x, if 3 circles of equal radii are drawn touching each other, then the relation between the side and the radius is given as x = 2r ($$\sqrt{3}$$ + 1)

Here r = 1, therefore the side of the equilateral triangle = 2 * 1 ($$\sqrt{3}$$ + 1) = 2($$\sqrt{3}$$ + 1)

Area of an equilateral triangle = $$\frac{\sqrt{3}}{4}$$ * $$x^{2}$$

Therefore Area = $$\frac{\sqrt{3}}{4}$$ * [$$2(\sqrt{3} + 1)] ^2$$

Area = $$\frac{\sqrt{3}}{4}$$ * 4 * (3 + 2*$$\sqrt{3}$$ + 1)

A = $$\sqrt{3}$$ * (4 + 2 * $$\sqrt{3}$$)

A = 4$$\sqrt{3}$$ + 6

Option B

Arun Kumar

How is this √3 +1 is coming corresponding to 2r(√3+1)

Posted from my mobile device

its 2(√3 +1) not √3 +1
2*r*(√3 +1) = 2*1*(√3 +1)
2(√3 +1)
and rest are the stated steps
Intern  B
Joined: 07 Aug 2018
Posts: 21
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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yashikaaggarwal wrote:
Shubham1213372 wrote:
CrackVerbalGMAT wrote:
In an equilateral triangle of side x, if 3 circles of equal radii are drawn touching each other, then the relation between the side and the radius is given as x = 2r ($$\sqrt{3}$$ + 1)

Here r = 1, therefore the side of the equilateral triangle = 2 * 1 ($$\sqrt{3}$$ + 1) = 2($$\sqrt{3}$$ + 1)

Area of an equilateral triangle = $$\frac{\sqrt{3}}{4}$$ * $$x^{2}$$

Therefore Area = $$\frac{\sqrt{3}}{4}$$ * [$$2(\sqrt{3} + 1)] ^2$$

Area = $$\frac{\sqrt{3}}{4}$$ * 4 * (3 + 2*$$\sqrt{3}$$ + 1)

A = $$\sqrt{3}$$ * (4 + 2 * $$\sqrt{3}$$)

A = 4$$\sqrt{3}$$ + 6

Option B

Arun Kumar

How is this √3 +1 is coming corresponding to 2r(√3+1)

Posted from my mobile device

its 2(√3 +1) not √3 +1
2*r*(√3 +1) = 2*1*(√3 +1)
2(√3 +1)
and rest are the stated steps

Thanks for you response.
However, I am confused on this part only --its 2(√3 +1).
How it is coming
PS Forum Moderator P
Joined: 18 Jan 2020
Posts: 1500
Location: India
GPA: 4
Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  [#permalink]

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1
yashikaaggarwal wrote:
The radius of circle is one
The smaller triangle is a right angle triangle with 30, 60 and 90 degree as angle whose sides are x, √3*x, 2x
where x = 1 (on comparing)
therefore √3*x = √3

The Side of triangle = √3 + 2 + √3
=> 2√3 + 2

The area of equilateral triangle = √3/4*side^2
=> √3/4*(2√3 + 2)
=> 4√3 + 6 or 6 + 4√3

VERBAL1 you might be able to understand better with diagram. its pure methodological question.

Shubham1213372 refer this
2(√3 + 1) is nothing but 2√3 + 2
where two is the rational part on the triangle side √3 is the irrational part, whose value is determined in the highlighted part above. Re: In an Equilateral triangle, 3 coins of radii 1 unit each are kept in   [#permalink] 16 Jul 2020, 10:38

# In an Equilateral triangle, 3 coins of radii 1 unit each are kept in  