Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 2008:00 AM PDT
-08:30 AM PDT
What’s in it for you- Live Profile Evaluation Chat Session with Jenifer Turtschanow, CEO, ARINGO. Come with your details prepared and ARINGO will share insights! Pre-MBA Role/Industry, YOE, Exam Score, C/GPA, ECs Post-MBA Role/ Industry & School List.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
04 Sep 2022, 10:53
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
44% (02:42) correct
56%
(03:24)
wrong
based on 36
sessions
History
Date
Time
Result
Not Attempted Yet
Note: Figure not drawn to scale.
In an isosceles triangle ABC shown above, AB = BC, and AC = CD = DF = FE = EB. What is the value of x ?
A. 10°
B. 15°
C. 20°
D. 30°
E. 40°
Fresh GMAT Club Tests' Question
Attachment:
Geometry.png
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
04 Sep 2022, 12:29
Kudos
Bookmarks
\(\triangle EBF\)
EF = EB
Therefore , \(\angle EBF = \angle BFE = x\)
\(\angle FEB = 180 - 2x \)
\(\triangle EFD\)
\(\angle DEF= 180- (180 - 2x) = 2x \)
EF = FD
Therefore , \(\angle DEF = \angle FDE = 2x\)
\(\angle EFD= 180- 4x\)
\(\triangle FDC\)
\(\angle DFC= 180- (180 - 3x) = 3x \)
DC = FD
Therefore , \(\angle DFC = \angle FCD = 3x\)
\(\angle FDC= 180- 6x \)
\(\triangle ADC\)
\(\angle ADC= 180- (180 - 4x) = 4x \)
DC = AC
Therefore , \(\angle ADC = \angle CDA = 4x\)
\(\triangle ABC\)
AB = BC
Therefore , \(\angle BAC = \angle BCA = 4x\)
Also, \(\angle BAC + \angle BCA + \angle ABC\) = 180
4x + 4x + x = 180
9x = 180
x = 20
IMO C
EF = EB
Therefore , \(\angle EBF = \angle BFE = x\)
\(\angle FEB = 180 - 2x \)
\(\triangle EFD\)
\(\angle DEF= 180- (180 - 2x) = 2x \)
EF = FD
Therefore , \(\angle DEF = \angle FDE = 2x\)
\(\angle EFD= 180- 4x\)
\(\triangle FDC\)
\(\angle DFC= 180- (180 - 3x) = 3x \)
DC = FD
Therefore , \(\angle DFC = \angle FCD = 3x\)
\(\angle FDC= 180- 6x \)
\(\triangle ADC\)
\(\angle ADC= 180- (180 - 4x) = 4x \)
DC = AC
Therefore , \(\angle ADC = \angle CDA = 4x\)
\(\triangle ABC\)
AB = BC
Therefore , \(\angle BAC = \angle BCA = 4x\)
Also, \(\angle BAC + \angle BCA + \angle ABC\) = 180
4x + 4x + x = 180
9x = 180
x = 20
IMO C
Attachments
Screenshot 2022-09-05 005834.png [ 159.28 KiB | Viewed 2048 times ]
11 Dec 2024, 10:17
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
