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Re: In an isosceles triangle PQR, if ∠Q = 80 degrees, then what is the ...
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07 Feb 2019, 11:13
This is an isosceles triangle, so two sides are equal and two angles must be of the same measure.
There are three cases:
1) angle Q is formed by two equal sides, so the other two angles (P and R) must be the same.
\(80 (angle Q) + angle P + angle R = 180\) (sum of all angles in a triangle)
\(angle P + angle R = 100\)
As mentioned before, angle P and angle R must be equal, hence P = 50 and R = 50.
2) angle Q is formed by the base and one of the sides, and the angle (let's say R) is formed by the base and the other side. It means, that Q=R, so \(P = 180-80-80 = 20\)
3) angle Q is formed by the base and one of the sides, and the angle (this time it's P) is formed by the base and the other side. It means, that Q=P, so P = 80
Sum of all possible values of angle \(P = 50 + 20 + 80 = 150\).
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50% (01:00) correct 
, let me correct it now
