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In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an [#permalink]
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Updated on: 17 Apr 2018, 01:39
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Foolproof method to Differentiate between Permutation & Combination Questions  Exercise Question #1In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, and 1 wicketkeeper and 1 allrounder can be selected from the pool of 7 batsmen, 6 bowlers, 3 wicketkeepers and 3 allrounders. OptionsA. 567 B. 1420 C. 2256 D. 2835 E. 5670 Learn to use the Keyword Approach in Solving PnC question from the following article: Article1: Learn when to “Add” and “Multiply” in Permutation & Combination questionsArticle2: Foolproof method to Differentiate between Permutation & Combination Questions
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In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an [#permalink]
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Updated on: 17 Apr 2018, 08:47
Solution Given:• We need to select a cricket team i.e. 11 players
o We need to select 5 batsmen from 7 batsmen and, o We need to select 4 bowlers from 6 bowlers and, o We need to select 1 wicket keeper from 3 wicket keepers and, o We need to select 1 allrounder from 3 allrounders. To find:• The number of ways we can from a cricket team out of 7 batsmen, 6 bowlers, 3 allrounders and 3 wicketkeepers available. Approach and Working:Since we need to select 5 batsmen, 4 bowlers, and 1 wicket keeper and 1 allrounder in the cricket team, • Hence, number of ways to form the cricket team= ways to select 5 batsmen from 7 batsmen* ways to select 4 bowlers from 6 bowlers * ways to select 1 wicket keeper from 3 wicket keepers * ways to select 1 allrounder from 3 allrounders
• Thus, total ways= \(^7c_5\)*\(^6c_4\)*\(^3c_1\)*\(^3c_1\)
• =21*15*3*3= 2835 Hence, in 2835 ways we can select a cricket team. Hence, option D is the correct answer. Answer: D
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Re: In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an [#permalink]
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11 Apr 2018, 23:46
EgmatQuantExpert wrote: Learn structured approach to identify permutation and combination question  Exercise Question #1
In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, and 1 wicketkeeper and 1 allrounder can be selected from the pool of 7 batsmen, 6 bowlers, 3 wicketkeepers and 3 allrounders.
Options A. 567 B. 1420 C. 2256 D. 2835 E. 5670 7C5 * 6C4 * 3C1 * 3C1 = 7!/(2!5!) * 6!/(2!4!) * 3!/(2!1!) * 3!/(2!1!) = 21*15*3*3 = 2835 > D imo, answer is option D.
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Re: In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an [#permalink]
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12 Apr 2018, 09:47
EgmatQuantExpert wrote: Learn structured approach to identify permutation and combination question  Exercise Question #1In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, and 1 wicketkeeper and 1 allrounder can be selected from the pool of 7 batsmen, 6 bowlers, 3 wicketkeepers and 3 allrounders. OptionsA. 567 B. 1420 C. 2256 D. 2835 E. 5670 Learn to use the Keyword Approach in Solving PnC question from the following article: Article1: Learn when to “Add” and “Multiply” in Permutation & Combination questionsArticle2: Learn structured approach to identify Permutation & Combination questions A simple PS question where one has to choose 5 batsman from 7 batsman, 4 bowlers out of 6 bowlers, 1 wicket keeper out of 3 wicket keepers and 1 all rounder from 3 allrounders. So according to combinations principles, the number of ways we can choose r items from n items is found out as nCr which equals to n!/((nr)!*r!). So here the solution is , 7C5*6C4*3C1*3C1 = 2835 (D)



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Re: In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an [#permalink]
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17 Apr 2018, 09:01
Hey everyone, The official solution to the question has been posted. Regards, Ashutosh eGMAT
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Re: In how many ways a cricket team consisting of 5 batsmen, 4 bowlers, an
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